pierret18811376

Inspiring

Answered

regular expression with brackets / comma and space

Forum|Forum|2 days ago
May 9, 2026
3 replies
31 views

Hello,

With the help of @Winfried Reng , for a text selection I could use the Find/change function with “regular expression” in order to add brackets around the text selection.

But now, inside this “regular expression” I would like to delete also the comma before this text selection.

So, I would like to select from the comma to the text selection (by example here : , soprano) and in a single regular expression, do two things : delete the comma and add brackets around the text selection.

How to do it ?

Correct answer frameexpert

Find: , (\b.+\b)

Change: ($1)

Make sure you remember the space at the beginning of the change.

Community Expert

Correct answer

Community Expert

Find: , (\b.+\b)

Change: ($1)

Make sure you remember the space at the beginning of the change.

www.frameexpert.com

pierret18811376Author

Inspiring

Hi @frameexpert

Your solution is working perfectly. In order to understand, why have you added “\b” inside the brackets ?

Community Expert

Community Expert

\b indicates a word boundary. I want to just get a whole word.

.+ by itself could get any number of characters, including multiple words.

www.frameexpert.com

pierret18811376Author

Inspiring

Finally, I have just found the solution. Here is the modified regular expression I have used :

pierret18811376Author

Inspiring

So, actually the regular expression is :

Find : (.+)

Change : ($1)

How to include also in the same regular expression the removing of the comma ?

So if I select : , soprano

I will have : (soprano)