Re-scaling a linked images to 100% in Illustrator

Bonjour,

A l'époque, j'ai éprouvé la même frustration que vous, c'est pourquoi j'ai adapté le script de John Wundes à ma convenance.

Possibilité de conserver ou non le redressement de l'image.

René

// JavaScript Document Illustrator to100pct.js
// elleere Sun, 25 February 2018 21:08:12 GMT
//Résoud un problème lorsque les images sont importées ou collées à partir du presse-papiers à 70%
// Ce script réinitialise les valeurs matricielles des RasterItems et PlacedItems afin qu'ils s'affichent à 100%.
// Plusieurs éléments raster et PlacedItem peuvent être transformés en même temps, les éléments de groupe seront introspectés.
// Addresses an issue when images are pasted from the clipboard at 70%
// This script resets the matrix values for pasted RasterItems and PlacedItems so they display at 100%.
// Multiple raster and PlacedItem items can be transformed at the same time, group items will be introspected.
// JS code (c) copyright: John Wundes ( john@wundes.com ) www.wundes.com
// copyright full text here:  http://www.wundes.com/js4ai/copyright.txt
var rd = 180/Math.PI;
var info = true;
var infoMatrix = false;
//-----
if(activeDocument && activeDocument.selection.length > 0) {
  testObjects(activeDocument.selection);
}

//-----
function testObjects(s) {
    for (var i = 0; i < s.length; i++) {
        if(s[i].typename == 'GroupItem') {
          testObjects(s[i].pageItems);
        }
        else
          if(s[i].typename=='RasterItem' || s[i].typename == 'PlacedItem') {
            if (infoMatrix) pointText("t = \r"+propObj(s[i].matrix),0,-20);
            fullsize(s[i]);
        }
    }
}
//-----
function getArrondi(nb,N) {
    //arrondi nb a N chiffres apres la virgule
    return Math.round(Math.pow(10,N)*nb)/Math.pow(10,N);
}
//-----
function fullsize(i) {
  var pos, m, deg, deg1, degArd, flip, scH, scV;
      pos = i.position;  // sauve position
      m = i.matrix
      deg1 = Math.atan2(i.matrix.mValueB, i.matrix.mValueA)*rd;
      degArd = getArrondi(deg1,3);
        try {
          deg = i.tags.getByName('BBAccumRotation').value*rd;
        } catch (error) {
          deg = 0;
        }

      flip = i.typename == 'PlacedItem' ? 1 : -1;
      unrotatedMatrix = app.concatenateRotationMatrix(m, deg * flip);
      scH = unrotatedMatrix.mValueA * 100;
      scV = unrotatedMatrix.mValueD * -100 * flip;
      if (info)
      alert("Horizontal Scale : "+scH.toFixed(3)+"\r"+"Vertical Scale : "+scV.toFixed(3)+"\rAngle = "+degArd+"\r"+deg) ;
      // Restore
      i.rotate(-deg);
      i.resize((100/scH)*100,(100/scV)*100);
      rotationTAG (i,0);
      redraw();
            if(!confirm ("Laisser redresser oui/non ?",false,"De Elleere")) {
              i.rotate(deg);
              // undo();
              rotationTAG(i,deg);
            }
}
//-----
function pointText(text,x,y) {
    var source = CoordinateSystem.ARTBOARDCOORDINATESYSTEM;
    var destination = CoordinateSystem.DOCUMENTCOORDINATESYSTEM;
    var pointText = activeDocument.textFrames.add();
    with (pointText) {
      contents = text;
      position = activeDocument.convertCoordinate([x,y],source,destination);
    }
}
//-----
function propObj(obj) {
    var l = "";
    for (k in obj) { // propriétés
    l += "\r"+k+" = "+eval("obj."+k);
    }
    return l;
}
//-----
 function rotationTAG (obj,a) {
  // Crée un nouvel objet Tag "BBAccumRotation" associé à obj d'angle a
  var rTAG = obj.tags.add();
      rTAG.name = "BBAccumRotation";
      rTAG.value = a*Math.PI/180; //angle en radians
}
//-----

I don't think Illustrator has a built-in way to do this, but it should definitely be possible with a script.

A script could read the current placed scale of each selected linked image, calculate the required scaling factor, and resize it so the final placed scale becomes exactly 50%, 100%, or any target value you specify.

If you're dealing with a lot of linked images, that would save a lot of time compared to calculating the scale manually for each one ngl.

This usually happens when linked images have been placed or transformed at different scale values, so Illustrator is showing them as something other than 100%. If you need consistent output, it is worth checking the image’s actual dimensions first, then deciding whether you want to reset the placed artwork to 100% or resize it proportionally.

Once the percentage difference is clear, you can apply the same scaling logic more consistently across the linked images.

How I reset the image back to 100%.
I use the scale panel and do a simple math: 10000/percentage shown in the link panel. 
Eg: 10000/108,35, it scales the image to 100%.

InDesign has this. You can see and easily edit any image's exact scale factor. (In the attached example, you have 64% of the original picture on both axes.) Adobe amazes me with its ability to NOT transfer successful solutions from one of its software to the others.

There used to be a way, but I'm finding the exact same issue.

I have placed images that are at 12.57% by 11.54%, but I want them to equal out.  I know I used to do it from the top header bar, but that's gone now. I can embed it, edit it Photoshop, even image trace it, but no way to adjust those percentages I can find.

The obvious place would to have a toggle next to the hieght and width of the image, so I could see the current dimensions in my units of choice, then see the percentage of origianl image size by toggling it. 

Benjamin,

Illy (job description Adobe Illustrator) is always eager to help, and she can make the calculations for you:

Just set the following value: desired scale*100 as one number (5000 for 50%), then add / then add current scale (65.635 as in your example). With those two numbers you get 5000/65.635, without needing to know that it is 76.1789%.

The same way, you can leave calculations based on two numbers using * or / or + or - in between to Illy; in many cases you can copy the difficult one from the source and insert it without typing it.