Inspiring

Question

Aktion überschreibt immer das Bild

Forum|Forum|5 years ago
January 11, 2021
2 replies
396 views

Hallo,

eine einfache Aktion macht Folgendes:

- Bild öffnen

- Bild speichern unter

- Bild schließen

Zweck ist die Umwandlung des Eingabebildes (AdobeRGB) in sRGB.

Leider wird immer das Ausgabebild mit dem gleichen Namen erzeugt, obwohl bei "speichern unter" in der Aufzeichnung nur der Ordner steht. Was mache ich falsch?

Danke und Gruß

Hermann-Josef

How to

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Bojan Živković11378569

Community Expert

Community Expert

From what I see your action is saving in Test_A folder, that is recorded in second step. It seems you have images for batch processing in the same Test_A folder and that make confusion, your images probably gets replaced during batch process.

If you have working solution that's fine, use it. I just want to point problematic 2. (second) step in your action: Speichern.

Inspiring

Thank you for pointing that out. That was my error, it was supposed to be saving in Test_s. So I did hit the wrong folder without noticing it!

Hermann-Josef

Community Expert

Community Expert

JJMack

Inspiring

Thank you for the screenshot.

Here is my input folder:

The ouput folder is empty.

Unfortunately it looks quite different from what I have:

Action:

Batch process:

This opens the two images but saves them with the same name, i.e. the name of the first image, in the output folder, as specified.

Then I realized that you use a different command, i.e. image processor:

But unfortunetaly this does not work either:

It created the jpg-version of the first image in the input folder (!) although a different output folder was specified:

It also created a subfolder JPEG in the output folder, which contains only the jpg-version of the second input image:

And then says it cannot process the first input tif-image (see message above).

I am completely confused now.

Hermann-Josef

Inspiring

Problem solved!

Using the image processor I must not activeate the action as well.

Using the batch processor still does not work as expected.

So I use the image processor. 🙂

Hermann-Josef