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alanp38746140
Participant
June 19, 2019
Answered

Arrange layer order by bounds area?

  • June 19, 2019
  • 2 replies
  • 863 views

Hi guys, as the title suggests, I'm trying to move the layer order by the their bounds area, this is where I got to right now, but getting an error. Not sure where I'm going wrong. Any suggestions & explanations is much appreciated!

var doc = app.activeDocument;

var layers = doc.artLayers;

function arrangeByArea()  {   

   

  for (var i = 0; i < doc.artLayers.length; i++)

  for (var y = 1; y < doc.artLayers.length -1; y++)

           var layerArea1 = (layers.bounds[2] - layers.bounds[0]) * (layers.bounds[3] - layers.bounds[1]);

           var layerArea2 = (layers.bounds[2] - layers.bounds[0]) * (layers.bounds[3] - layers.bounds[1]);

          if (layerArea1 >= layerArea2) {

               layers.move(layers, ElementPlacement.PLACEAFTER);

    

    }

  }

arrangeByArea();

This topic has been closed for replies.
Correct answer r-bin
var doc = app.activeDocument;
var layers = doc.artLayers;
function arrangeByArea() 
    { 
    for (var i = 0; i < layers.length-1; i++)
        {
        var layerArea1 = (layers.bounds[2] - layers.bounds[0]) * (layers.bounds[3] - layers.bounds[1]);
        var layerArea2 = (layers[i+1].bounds[2] - layers[i+1].bounds[0]) * (layers[i+1].bounds[3] - layers[i+1].bounds[1]);
        if (layerArea1 >= layerArea2)
            {
            layers.move(layers[i+1], ElementPlacement.PLACEAFTER);
            i = -1; // restart the cycle
            }                   
        }
    }
arrangeByArea();
alert("Done");

I will not explain. Sorry. I find it difficult in English.

UPD.

Need to change >= to >.
Otherwise, with the same area, the script will loop endlessly.

2 replies

Chuck Uebele
Community Expert
Chuck UebeleCommunity Expert
Community Expert
June 20, 2019

This is my version: a script that I've used to arrange layers from the smallest area to the largest. I put the area of each layer into an array, the sort the array, then move the layers.

#target photoshop
var docRef = activeDocument
var sizeArray = new Array()
for(var i=0;i<docRef.layers.length;i++){
    docRef.activeLayer = docRef.layers
    var area = (Number(docRef.activeLayer.bounds[2]) -Number(docRef.activeLayer.bounds[0]))*(Number(docRef.activeLayer.bounds[3]) -Number(docRef.activeLayer.bounds[1]))
    var area2 = area + 1000000000000
    sizeArray = area2+':'+docRef.activeLayer.name
   
    sizeArray.sort()
    
    }
var layLen = docRef.layers.length
for(var j=0;j<sizeArray.length;j++){
    var layName = sizeArray.split(':')[1];
    
    docRef.activeLayer = docRef.layers.getByName (layName)
    docRef.activeLayer.move(docRef.layers[layLen-1],ElementPlacement.PLACEAFTER)
    }
    R
    r-bin
    Legend
    June 20, 2019

    There will be problems if the layers have the same name.

      Chuck Uebele
      Community Expert
      Chuck UebeleCommunity Expert
      Community Expert
      June 20, 2019

      That's true, but since I wrote the script for my own use, I never have layers with the same name.

      R
      r-binCorrect answer
      Legend
      June 19, 2019
      var doc = app.activeDocument;
      var layers = doc.artLayers;
      function arrangeByArea() 
          { 
          for (var i = 0; i < layers.length-1; i++)
              {
              var layerArea1 = (layers.bounds[2] - layers.bounds[0]) * (layers.bounds[3] - layers.bounds[1]);
              var layerArea2 = (layers[i+1].bounds[2] - layers[i+1].bounds[0]) * (layers[i+1].bounds[3] - layers[i+1].bounds[1]);
              if (layerArea1 >= layerArea2)
                  {
                  layers.move(layers[i+1], ElementPlacement.PLACEAFTER);
                  i = -1; // restart the cycle
                  }                   
              }
          }
      arrangeByArea();
      alert("Done");

      I will not explain. Sorry. I find it difficult in English.

      UPD.

      Need to change >= to >.
      Otherwise, with the same area, the script will loop endlessly.

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