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Group Selected Layers

Forum|Forum|7 years ago
August 12, 2018
4 replies
4738 views

Is it possible to group all selected layers individually? Each layer would remain within the respective group. All help will be treasured.

Actions and scripting

This topic has been closed for replies.

Correct answer Stephen Marsh

but, but 🙂 can you make it to work for each layer when selected multiple layers?

Try this:

#target photoshop

function main() {

    ///// Process selected layers - from jazz-y /////
    var s2t = stringIDToTypeID;
    (r = new ActionReference()).putProperty(s2t('property'), p = s2t('targetLayersIDs'));
    r.putEnumerated(s2t('document'), s2t('ordinal'), s2t('targetEnum'));
    var lrs = executeActionGet(r).getList(p),
        sel = new ActionReference();
    for (var i = 0; i < lrs.count; i++) {
        sel.putIdentifier(s2t('layer'), p = lrs.getReference(i).getIdentifier(s2t('layerID')));
        (r = new ActionReference()).putIdentifier(s2t('layer'), p);
        (d = new ActionDescriptor()).putReference(s2t("target"), r);
        executeAction(s2t('select'), d, DialogModes.NO);
    //////////

        var layerName = activeDocument.activeLayer.name;
        setFromLayer("[Merge]" + layerName);
        setFromLayer("[Bone]" + layerName);

        ///// Functions /////

        function setFromLayer(layNme) {
            function s2t(s) {
                return app.stringIDToTypeID(s);
            }
            var descriptor = new ActionDescriptor();
            var descriptor2 = new ActionDescriptor();
            var reference = new ActionReference();
            var reference2 = new ActionReference();
            reference.putClass(s2t("layerSection"));
            descriptor.putReference(s2t("null"), reference);
            reference2.putEnumerated(s2t("layer"), s2t("ordinal"), s2t("targetEnum"));
            descriptor.putReference(s2t("from"), reference2);
            descriptor2.putString(s2t("name"), layNme);
            descriptor.putObject(s2t("using"), s2t("layerSection"), descriptor2);
            executeAction(s2t("make"), descriptor, DialogModes.NO);
        }
    }
}
app.activeDocument.suspendHistory("Undo Script", "main()");

Greg von Neulich

Known Participant

we made a Photoshop plug-in that can do this. The unlimited version is 12$.

Full Version (12$):
https://exchange.adobe.com/apps/cc/c36e02fb/swift

Trial Version (Limited to 5 Actions):
https://exchange.adobe.com/apps/cc/412c1dcd/swift-trial-version

Its also a big help with getting the layers selected.

A

aleksanderk54154416

Participating Frequently

Helo!

I need script that will make group from a layer and another group from that group with prefixes.

for example result will look like this:

is that possible?

Stephen Marsh

Community Expert

@aleksanderk54154416 – Something like this?

var layerName = activeDocument.activeLayer.name;
setFromLayer("[Merge]" + layerName);
setFromLayer("[Bone]" + layerName);

function setFromLayer(layNme) {
	function s2t(s) {
		return app.stringIDToTypeID(s);
	}
	var descriptor = new ActionDescriptor();
	var descriptor2 = new ActionDescriptor();
	var reference = new ActionReference();
	var reference2 = new ActionReference();
	reference.putClass( s2t( "layerSection" ));
	descriptor.putReference( s2t( "null" ), reference );
	reference2.putEnumerated( s2t( "layer" ), s2t( "ordinal" ), s2t( "targetEnum" ));
	descriptor.putReference( s2t( "from" ), reference2 );
	descriptor2.putString( s2t( "name" ), layNme );
	descriptor.putObject( s2t( "using" ), s2t( "layerSection" ), descriptor2 );
	executeAction( s2t( "make" ), descriptor, DialogModes.NO );
}

A prompt could be added so that you type in the name of the prefix into a GUI, rather than having it hard-coded.

A

aleksanderk54154416

Participating Frequently

It works man! I am going to cry now :))

thanx a lot

K

KiriK

Participant

Hi all,

Is it possible to make a script or action that both group and name the group the file name at the same time?

Example:

Layer01

Layer02

I want to group them and name each group the layer names.

(exactly the same name as the layer or image)

Group name:

Layer01

Layer02

Layer03

Stephen Marsh

Community Expert

Try this:

#target Photoshop

// community.adobe.com/t5/Photoshop/Action-Script-to-group-layers-and-naming/td-p/10635514

// Select all layers - Except Background "Image" Layer
app.runMenuItem(stringIDToTypeID('selectAllLayers')); 

/*
// Select all layers...
var actionDescriptor = new ActionDescriptor();
var actionReference = new ActionReference();
actionReference.putEnumerated( charIDToTypeID( "Lyr " ), charIDToTypeID( "Ordn" ), charIDToTypeID( "Trgt" ) );
actionDescriptor.putReference( charIDToTypeID( "null" ), actionReference );
executeAction( stringIDToTypeID( "selectAllLayers" ), actionDescriptor, DialogModes.NO );
*/

/*
// Select all layers  
// =======================================================  
var idselectAllLayers = stringIDToTypeID( "selectAllLayers" );  
var desc14 = new ActionDescriptor();  
var idnull = charIDToTypeID( "null" );  
var ref8 = new ActionReference();  
var idLyr = charIDToTypeID( "Lyr " );  
var idOrdn = charIDToTypeID( "Ordn" );  
var idTrgt = charIDToTypeID( "Trgt" );  
ref8.putEnumerated( idLyr, idOrdn, idTrgt );  
desc14.putReference( idnull, ref8 );  
executeAction( idselectAllLayers, desc14, DialogModes.NO );  
*/

// community.adobe.com/t5/Photoshop/Group-Selected-Layers/td-p/9983092#10555610
function sTT(v) {return stringIDToTypeID(v)}
(ref = new ActionReference()).putEnumerated
(sTT('document'), sTT('ordinal'), sTT('targetEnum'));
cnt = (lst = executeActionGet(ref).getList(sTT('targetLayersIDs'))).count
for(i = 0; i < cnt;) {
     id = lst.getReference(i++).getIdentifier();
     (ref1 = new ActionReference()).putClass(sTT('layerSection'));
     (dsc1 = new ActionDescriptor()).putReference(sTT('null'), ref1);
     (ref2 = new ActionReference()).putIdentifier(sTT('layer'), id)
     dsc1.putReference(sTT('from'), ref2);
     nme = executeActionGet(ref2).getString(sTT('name'));
     (dsc2 = new ActionDescriptor()).putString(sTT('name'), nme)
     dsc1.putObject(sTT('using'), sTT('layerSection'), dsc2)
     executeAction(sTT('make'), dsc1)
}

U

unsandj

Participant

Hi, thanks for the script! But could you help me? I want to add a mask to the name. To rename the group like this: [slovo:name_layer]

Kukurykus

Legend

CC 2018:

function sTT(v) {return stringIDToTypeID(v)}
(ref = new ActionReference()).putEnumerated
(sTT('document'), sTT('ordinal'), sTT('targetEnum'));
cnt = (lst = executeActionGet(ref).getList(sTT('targetLayersIDs'))).count
for(i = 0; i < cnt;) {
     id = lst.getReference(i++).getIdentifier();
     (ref1 = new ActionReference()).putClass(sTT('layerSection'));
     (dsc1 = new ActionDescriptor()).putReference(sTT('null'), ref1);
     (ref2 = new ActionReference()).putIdentifier(sTT('layer'), id)
     dsc1.putReference(sTT('from'), ref2);
     nme = executeActionGet(ref2).getString(sTT('name'));
     (dsc2 = new ActionDescriptor()).putString(sTT('name'), nme)
     dsc1.putObject(sTT('using'), sTT('layerSection'), dsc2)
     executeAction(sTT('make'), dsc1)
}

P

Ps-DesignAuthor

Known Participant

Phenomenal your script Kukurykus

You are a genius. Thank you.

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