How I can get last Index of gradient in list of gradients ?

Question

I created .jsx file from action and have a line with text :

ref1.putIndex(cTID('Grdn'), 1);

but

ref1.putIndex(cTID('Grdn'), -1);

in

  function step1(enabled, withDialog) {
    if (enabled != undefined && !enabled)
      return;
    var dialogMode = (withDialog ? DialogModes.ALL : DialogModes.NO);
    var desc1 = new ActionDescriptor();
    var ref1 = new ActionReference();
    ref1.putIndex(cTID('Grdn'), -1);
    desc1.putReference(cTID('null'), ref1);
    executeAction(sTID('delete'), desc1, dialogMode);
  };

don't work for last gradients in list, I try to created action with 3 steps:
1)create new gradient
2)delete this gradient
3)delete last gradient -1
I converted this action in jsx file and try to run, but this script didn't work without edits.
If you have any ideas - thank you.

Kukurykus · Accepted Answer

function sTT(v) {return stringIDToTypeID(v)}
(ref = new ActionReference()).putProperty(sTT('property'), pM = sTT('presetManager'))
ref.putEnumerated(sTT('application'), sTT('ordinal'), sTT('tergetEnum'))
cnt = executeActionGet(ref).getList(pM).getObjectValue(2).getList(sTT('name')).count;
(ref = new ActionReference()).putIndex(sTT('gradientClassEvent'), cnt);
(dsc = new ActionDescriptor()).putReference(sTT('null'), ref)
executeAction(sTT('delete'), dsc)

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