Skip to main content
natrev
natrev
Legend
October 16, 2015
Answered

Is it possible to get layer, layerset and layer with in layerset status...!!!

  • October 16, 2015
  • 1 reply
  • 823 views

Hi Everyone!,

Is it possible to get layer, layerset and layer with in layerset status. Since I have faced big problem beyond this.

I have an one PS document which is contain collection of layer, collection layersets with layer. I need apply function for each layer and layersets and all layers with in layerset.

Also I tried one code but its getting error. Please help me to out this code...

-yajiv

#target photoshop

app.bringToFront();

$.level=2;

var docRef = app.activeDocument;

var log="";

var x=0;

var n=Number(docRef.layers.length)-1;

for (i=0;i<n;i++){

    var tm=String(docRef.layers);

    var isLayer=tm.lastIndexOf("ArtLayer");

    var isLayerSet=tm.lastIndexOf("LayerSet");

    if(isLayer!=-1){

        Check_LayerStructure(docRef.layers,"Layer");

    }

    if(isLayerSet!=-1){

        Check_LayerStructure(docRef.layerSets,"LayerSets");

        x=x+1;

        }

}

function Check_LayerStructure(objLayer,objflag,x){       \  

    if(objflag=="Layer"){

        LayetStructure(objLayer,objLayer.name,BlendMode.NORMAL,100,100,0,true," Layer ");

        }

    else if(objflag=="LayerSets"){

        LayetStructure(objLayer,objLayer.name,BlendMode.PASSTHROUGH,100,100,1,true," Set ");

        m=Number(objLayer.layers.length)

      

        for (j=0;j<m;j++){

            var tm=String(objLayer.layers);

            var isLayer=tm.lastIndexOf("ArtLayer");

            var isLayerSet=tm.lastIndexOf("LayerSet");

            if(isLayer!=-1){

                Check_LayerStructure(objLayer.layers,"Layer");

            }

            if(isLayerSet!=-1){

                Check_LayerStructure(objLayer.layerSets,"LayerSets",x);

                }

    } // Layerset Loop

}// I For Loop

}//Function loop

function LayetStructure(layerRef,L,bMode,Opt,fillOpt,S,layVisible,Lref){

    if(layerRef.blendMode!=bMode){

          if (confirm (L + Lref+"belend mode was wrong...!!!\n"+"Do you want to change....?")){

              layerRef.blendMode=bMode;

              log=log+"- " +L+ Lref+ "belend mode was changed...!!!\n\n";

              e=1;

            }      

        }

   if(layerRef.opacity!=Opt) {

          if (confirm (L + Lref+ "Opacity was "+Math.round(layerRef.opacity)+"%...!!!\n"+"Do you want to change....?")){

              layerRef.opacity=Opt;

             log=log+"- " + L + Lref+ "Opacity was changed to 100...!!!\n\n";

              e=1;

            }      

       }

 

      if(layerRef.fillOpacity!=fillOpt && S==0) {

          if (confirm (L + Lref+ "Fill was "+Math.round(layerRef.fillOpacity)+"%...!!!\n"+"Do you want to change....?")){

              layerRef.fillOpacity=fillOpt;

              log=log+"- " + L + Lref+ "Fill was changed to 100...!!!\n\n";

              e=1;

            }      

       }

 

    if(layerRef.visible!=layVisible) {

          if (L + Lref+ "eye was off..!!!\n"+"Do you want to change....?"){

              layerRef.visible=layVisible;

              log=log+"- " + L + Lref+ "eye was turn into on...!!!\n\n";

              e=1;

            }      

       }

  }

This topic has been closed for replies.
Correct answer c.pfaffenbichler

Action Manager code would naturally be faster, but if you should be more comfortable with DOM code this might be of use to you.

#target photoshop

var theLayers = collectLayers(app.activeDocument, []);

alert (theLayers.join("\n"));

////// function collect all layers //////

function collectLayers (theParent, allLayers) {

  if (!allLayers) {var allLayers = new Array}

  else {};

  var theNumber = theParent.layers.length - 1;

  for (var m = theNumber; m >= 0;m--) {

  var theLayer = theParent.layers;

// apply the function to layersets;

  if (theLayer.typename == "ArtLayer") {

  allLayers.push([theLayer, theLayer.blendMode, theLayer.opacity, theLayer.fillOpacity])

  }

  else {

  allLayers = (collectLayers(theLayer, allLayers))

// this line includes the layer groups;

  allLayers.push([theLayer, theLayer.blendMode, theLayer.opacity, theLayer.fillOpacity]);

  }

  };

  return allLayers

  };

1 reply

c.pfaffenbichler
Community Expert
c.pfaffenbichlerCommunity Expert
Community Expert
October 16, 2015

What exactly do you need to get?

Please provide a screenshot of the Layers Panel and a text representing the information you want to get for those Layers/LayerSets …

natrev
natrevAuthor
Legend
October 17, 2015

Hi c.pfaffenbichler,

Thanks for your reply. What I need exactly mentioned below.

1. I need to check Layer property whether layer has 100% opacity and blend mode Normal

2. As well as check layerset property whether layerset has 100% fillopacity and blend mode is PASS THROUGH

3. In Photoshop document has many layer and layerset. As well as the layerset has many layer and layerset.

4. I need create recursive function to check all layers and layerset....

Thanks in advance.

-- yajiv

c.pfaffenbichler
Community Expert
c.pfaffenbichlerCommunity ExpertCorrect answer
Community Expert
October 17, 2015

Action Manager code would naturally be faster, but if you should be more comfortable with DOM code this might be of use to you.

#target photoshop

var theLayers = collectLayers(app.activeDocument, []);

alert (theLayers.join("\n"));

////// function collect all layers //////

function collectLayers (theParent, allLayers) {

  if (!allLayers) {var allLayers = new Array}

  else {};

  var theNumber = theParent.layers.length - 1;

  for (var m = theNumber; m >= 0;m--) {

  var theLayer = theParent.layers;

// apply the function to layersets;

  if (theLayer.typename == "ArtLayer") {

  allLayers.push([theLayer, theLayer.blendMode, theLayer.opacity, theLayer.fillOpacity])

  }

  else {

  allLayers = (collectLayers(theLayer, allLayers))

// this line includes the layer groups;

  allLayers.push([theLayer, theLayer.blendMode, theLayer.opacity, theLayer.fillOpacity]);

  }

  };

  return allLayers

  };

Terms & ConditionsAccessibility statement
Using the community Terms of use Privacy Cookie preferences Do not sell or share my personal information ad choicesAdChoices