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A
Anonymous
March 8, 2011
Question

Selecting pixels in a picture and changing their color with a script

  • March 8, 2011
  • 1 reply
  • 3015 views

Hi, I'm brand new to photoshop scripting, and I want to make a script that takes every pixel of a color and replaces it with a new color,

I'm having the hardest time finding any information on the internet on how to do it though.

I do have some background in other coding, so the concepts are not new, just the language and functions.

I know there's tools and filters already, but I want to make a script so I can add features.

Any help would be appreciated.

Thank you!

(P.S. Is there a way to open and read code of a pre-exsisting filter, or is that impossible?)

This topic has been closed for replies.

1 reply

c.pfaffenbichler
Community Expert
c.pfaffenbichlerCommunity Expert
Community Expert
March 8, 2011

When you write »pixel of a color« do you really mean one specific RGB-value?

Because then it might be easiest to just create one pixel of the color, load that as a Selection and use

Selection.similar(0, false)

and use the Selection thus produced to create a Solid Color Layer.

Having the Script iterate through each pixel’s values individually might take considerably longer.

(P.S. Is there a way to open and read code of a pre-exsisting filter, or is that impossible?)

I wonder if what Scripting offers is what you are after if you want to muck about with Filters’ code.

Have you checked out Pixel Bender yet?

A
Anonymous
March 8, 2011

Yes, one specific color value, RBG

Why would pixel bender be useful? I tried it and it's just a bunch of filters, I want to edit filters, am I missing something?

Thanks

Paul Riggott
Paul Riggott
Inspiring
March 8, 2011

To create your own filters you would need to download the SDK I think you might find an example of a filter.

With Photoshop this might be close...

main();
function main(){
if(!documents.length) return;
var sColour =new SolidColor;
sColour.rgb.hexValue ='245887'; 
selectColorRange(0,sColour);
try{
 var SB = activeDocument.selection.bounds;
    }catch(e){return;}
var FillColour =new SolidColor;
FillColour.rgb.hexValue = 'ff0000';
activeDocument.selection.fill(FillColour,ColorBlendMode.NORMAL);
activeDocument.selection.deselect();
}
function selectColorRange( fuzz, solidColor){
var scaleA = (solidColor.lab.a + 128.5) / 256;
    var desc11 = new ActionDescriptor();
    desc11.putInteger( charIDToTypeID( "Fzns" ), fuzz );
        var desc12 = new ActionDescriptor();
        desc12.putDouble( charIDToTypeID( "Lmnc" ), solidColor.lab.l );
        desc12.putDouble( charIDToTypeID( "A   " ), solidColor.lab.a + scaleA);
        desc12.putDouble( charIDToTypeID( "B   " ), solidColor.lab.b + scaleA);
    desc11.putObject( charIDToTypeID( "Mnm " ), charIDToTypeID( "LbCl"), desc12 );
    desc11.putObject( charIDToTypeID( "Mxm " ), charIDToTypeID( "LbCl" ), desc12 );
executeAction( charIDToTypeID( "ClrR" ), desc11, DialogModes.NO );
};


Using Christophs suggestion...

//Use 1 pixel to colour
app.activeDocument.colorSamplers.removeAll();
var mySampler = app.activeDocument.colorSamplers.add([new UnitValue(1,'px'),new UnitValue(1,'px' )]);
//Get original colour
var oColour = new SolidColor();
oColour = mySampler.color;
app.activeDocument.colorSamplers.removeAll();
//Select colour
var sColour = new SolidColor();
sColour.rgb.hexValue ='31618f';
activeDocument.selection.select([[0,0],[1,0],[1,1],[0,1]], SelectionType.REPLACE, 0, false);
activeDocument.selection.fill(sColour,ColorBlendMode.NORMAL);
//Replacement Colour
var rColour = new SolidColor();
rColour.rgb.hexValue ='ff0000';
activeDocument.selection.similar(0, false);
activeDocument.selection.fill(rColour,ColorBlendMode.NORMAL);
activeDocument.selection.deselect();
//Replace original colour.
activeDocument.selection.select([[0,0],[1,0],[1,1],[0,1]], SelectionType.REPLACE, 0, false);
activeDocument.selection.fill(oColour,ColorBlendMode.NORMAL);
activeDocument.selection.deselect();
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