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Polycontrast
Inspiring
December 4, 2022
Answered

Timestamp calculation

  • December 4, 2022
  • 1 reply
  • 1472 views

I would like to calculate the difference between 2 timestamps. The timestamp is generated from the new Date() method and is formatted as hh:mm:ss in military time. 

 

What needs to take place to calculate the difference between 2 timestamps?

Does the time stamp need to be converted to seconds to calculate the difference and then reconvert to the hh:mm:ss time format?

 

function militaryTime() {
 // Get the time and format it 
 var digital = new Date(); 
 var hours = digital.getHours(); 
 var minutes = digital.getMinutes(); 
 var seconds = digital.getSeconds();
 
 //military format
 if (hours <= 9) hours = "0" + hours;
 if (minutes <= 9) minutes = "0" + minutes;
 if (seconds <= 9) seconds = "0" + seconds;
 
 var time = hours + ":" + minutes + ":" + seconds;
 
 return time
}
 
alert(militaryTime());

oes

 

This topic has been closed for replies.
Correct answer Mike Bro

Hello @Polycontrast,

 

Take a look at the example below...

 

var date1 = new Date("08/05/2015 23:41:20");
var date2 = new Date("08/06/2015 02:56:32");

var diff = date2.getTime() - date1.getTime();

var msec = diff;
var hh = Math.floor(msec / 1000 / 60 / 60);
msec -= hh * 1000 * 60 * 60;
var mm = Math.floor(msec / 1000 / 60);
msec -= mm * 1000 * 60;
var ss = Math.floor(msec / 1000);
msec -= ss * 1000;

alert(hh + ":" + mm + ":" + ss);

 

Regards,

Mike

1 reply

M
Mike BroCorrect answer
Legend
December 5, 2022

Hello @Polycontrast,

 

Take a look at the example below...

 

var date1 = new Date("08/05/2015 23:41:20");
var date2 = new Date("08/06/2015 02:56:32");

var diff = date2.getTime() - date1.getTime();

var msec = diff;
var hh = Math.floor(msec / 1000 / 60 / 60);
msec -= hh * 1000 * 60 * 60;
var mm = Math.floor(msec / 1000 / 60);
msec -= mm * 1000 * 60;
var ss = Math.floor(msec / 1000);
msec -= ss * 1000;

alert(hh + ":" + mm + ":" + ss);

 

Regards,

Mike

P
PolycontrastAuthor
Inspiring
December 5, 2022

Many thanks, the code looks good. I will test it to see how it works.

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