Adobe Prepare Form / 3rd Drop Down Menu dependent on selections for BOTH menus 1 and 2.

You're close! The issue with using a Mouse Down script on the third dropdown ("Outer-Box") is that it resets the options every time the field is clicked — even if nothing changed.

✅ A better approach is to use a Calculation script in the third dropdown. Here's how to do it:

// JavaScript - Acrobat Dropdown Dependency
var food = this.getField("Food").value;
var inner = this.getField("Inner-Pkg").value;

if (food === "Liquid" && inner === "Carton") {
event.target.setItems(["Option A", "Option B"]);
} else if (food === "Liquid" && inner === "Bottle") {
event.target.setItems(["Option C", "Option D", "Option E", "Option F"]);
} else if (food === "Solid" && inner === "Crate") {
event.target.setItems(["Option G", "Option H"]);
} else {
event.target.setItems(["-- Select an option --"]);
}

This method ensures that "Outer-Box" only shows valid choices based on the combined selection of "Food" and "Inner-Pkg".

Let me know if you'd like help building the logic for all 9 combinations — happy to assist!

Cheers,
lex

Use the following Mouse Down action script in "Outer-Box":

var food=this.getField("Food").value;

var inner=this.getField("Inner-Pkg").value;

if(food=="Liquid" && inner=="Carton")

{event.target.setItems(["","A", "B", "C"])} else

if(food=="Liquid" && inner=="Bottle")

{event.target.setItems(["","D", "E", "F"])} else

//if ....etc.

{event.target.setItems([""])}