Three drop-down menus with condition.
Hello. As a continuation of the question (Two drop-down menus with condition.)...
There are three drop down menus
| DROP | DROP 2 | DROP 3 |
| A | A | A |
| B | B | B |
| C | C | C |
| D | D | D |
| E | E | E |
| F | F | F |
| G | G | G |
| H | H | H |
Which script can be used to exclude repetitions in each subsequent menu?
For example, in the DROP menu I selected "A",
then in the DROP 2 and DROP 3 menus exclude "A",
and after selecting "B" in DROP 2, exclude it from DROP 3 (and "A", respectively).
Of course, the entries in the menu can be selected in free order (and not alphabetically or in order)
I am assuming that every field (A, B, C, etc.) need to assign a value.
But what script can I use for this, I don’t know?
Unfortunately, I did not find this example either on YouTube or on other forums.
Thank you.
