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Arbitrary Mask Question

Forum|Forum|1 year ago
November 2, 2024
2 replies
1318 views

I'm hoping someone can me clean up the following Arbitrary Mask javascript I'd like to use on a form. My goal is to change it to just 3 alphabet letters. I can't seem to get the script right. Here is where i'm at with this and it's not working.

if(event.willCommit){
var input = event.value;
var pattern = /^(|\[A-Za-z]{3}$|$/);
if (!pattern.test(input)) {
event.rc = false;
app.alert("Input must be either 3 alphabet letters, or blank.");}}

Thank you in advance for any ideas on how to make this work!

This topic has been closed for replies.

Correct answer JR Boulay

You don't need JavaScript to do this:

A - Accepts only letters (A–Z, a-z).
X - Accepts spaces and most printable characters, including all characters available on a standard keyboard and ANSI characters in 32–126 and 128–255.
O - The letter “O” accepts alphanumeric characters (A–Z, a-z, and 0–9).
9 - Accepts only numeric characters (0–9).

JR Boulay

Correct answer

Community Expert

You don't need JavaScript to do this:

A - Accepts only letters (A–Z, a-z).
X - Accepts spaces and most printable characters, including all characters available on a standard keyboard and ANSI characters in 32–126 and 128–255.
O - The letter “O” accepts alphanumeric characters (A–Z, a-z, and 0–9).
9 - Accepts only numeric characters (0–9).

Acrobate du PDF, InDesigner et Photoshopographe

stepheng54012748Author

Known Participant

Yes! This is the answer and THANK YOU!!

try67

Community Expert

Use this:

var pattern = /^[a-z]{3}$/i);

stepheng54012748Author

Known Participant

Here is what i input and it did not work.

if(event.willCommit){
var input = event.value;
var pattern = /^[a-z]{3}$/i);
if (!pattern.test(input)) {
event.rc = false;
app.alert("Input must be either 3 alphabet letters, or blank.");}}

try67

Community Expert

Where did you place it? Under which event?

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