Find which range bracket/tier a number falls into

[Handycam]

I have to take a number and figure out which "tier" it falls into.

For example, let's say I have a table that has three tiers "economy" "typical" "deluxe".  From 0-12 is economy, 13-20 is typical, 21-30 is deluxe. My actual table has many more levels, but this is the concept.

What's the fastest and easiest way to do that?  I was going to use a switch statement starting with the highest, but it doesn't look like that can be done

[kglad]

if there's no pattern to the tiers, add them to an array and use your array to categorize tiers.

[Handycam]

I thought of an array, but I'm still not sure how to do the comparison.

Not sure if I'm explaining it correctly, but I would have a number and then need to know which tier that number falls into (out of 3 in my example).

If I make an array out of the tiers [economy,typical,deluxe] how would I know if the user types "12" which member of the array to return?

[Handycam]

I suppose I could do it as an ordered array or dictionary

{economy:1},{economy:2}...

[kglad · Accepted solution]

you can call tierF() passing any number and it will return the tier label:

var labelA:Array=["economy","typical",etc];

var tierA:Array=[[0,12],[13-20],etc];

function tierF(n:Number):String{

for(var i:Number=0;i<tierA.length;i++){

if(n>=tierA[0]&&n<=tierA[1]){

return labelA;

}

}

}

[Handycam]

Thanks much, I get it now (I think).  I had to change your function a bit so it always returns a value:

private var labelA:Array=["economy","typical"]; private var tierA:Array=[[0,12],[13,14,20]];                                                private function tierF(n:Number):String{                     var s:String = "";                     for(var i:Number=0;i<tierA.length;i++){                          if(n>=tierA[0]&&n<=tierA[1]){                               s =  labelA;                          }                     }                     return s;                }

So trace tierF(14) traces "typical".

I'm assuming your "13-20" was shorthand, since that didn't work as is.

[kglad]

you're welcome.

but, each element of tierA needs only 2 elements.  and my function is prefered because the loop stops when the correct tier is found.  if no tier is found an error message would be even better:

private var labelA:Array=[economy,typical];
private var tierA:Array=[[0,12],[13,20]];
               
               
               function tierF(n:Number):String {
     for (var i:Number=0; i<tierA.length; i++) {
          if (n>=tierA[0]&&n<=tierA[1]) {
               return labelA;
          }
     }
     return "out of range";
}

[Handycam]

Oh, I see now. Very clever indeed.