how can I get the length of a layer in JSFL script?

[Sunny_Y]

Hi

I wanted to change shapes' stroke thickness of all symbols at once.

Using following script somehow only changes thickness on 1st frame of a  symbol.

What I think I need is to get the length of a layer and make function repeat.

When I tried  (var i = 0; i<3; i++) it worked fine.

I am a newbie to JSFL. Can anyone help?

var stroke_width = 1.6;

var scale_Type = "none";

fl.trace("Changing all strokes width to "  + stroke_width);

function changeStroke(element, width, scale)

{

    if (element.elementType == "shape") {

        var stroke = element.getCustomStroke();

        stroke.thickness = width;

        stroke.scaleType = scale;

        element.setCustomStroke(stroke);

        // recurse for groups

        for (var iSubE in element.members) {

            var sub_element = element.members[iSubE];

            changeStroke(sub_element, width, scale);

        }

    }

}

var libItems = fl.getDocumentDOM().library.items;

for (var item_it in libItems)

{

    var item = libItems[item_it];

    if (item == undefined || item.symbolType == undefined)

    {

        continue;

    }

     var timeline = item.timeline;

     var tlArray = fl.getDocumentDOM().getTimeline().getSelectedLayers();

    for (var layer_it in timeline.layers)

  {

  for (var i = 0; i<tlArray.length; i++)

    {

        var layer = timeline.layers[layer_it];

        var frame = layer.frames;

        for (var element_it in frame.elements)

{

        var frame = layer.frames;

}

        for (var element_it in frame.elements)

        {

            var element = frame.elements[element_it];

            changeStroke(element, stroke_width, scale_Type);

        }

    }

  }

}

[UDESCO · Accepted solution]

This gives you the length of a particular layer :

     var layerIndex = 0;

     fl.getDocumentDOM().getTimeline().layers[layerIndex].frames.length;

This shows max frames including all the layers in timeline:

     fl.getDocumentDOM().getTimeline().frameCount;