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Hi,
I've got this code that is looking for the closest number to 0 in my array :
var tideArray = new Array();
tideArray.push({tide:"haute", difference: "-14"});
tideArray.push({tide:"haute", difference: "3"});
tideArray.push({tide:"basse", difference: "-4"});
tideArray.push({tide:"basse", difference: "8"});
if (tideArray.length > 0)
{
var minItem: Object = tideArray[0];
for (var index:int = 1; index < tideArray.length; index++)
{
if (Math.abs(tideArray[index].difference) < Math.abs(minItem.difference))
{
minItem = tideArray[index];
}
}}
trace(minItem.difference) // OUTPUT is 3 in this case
Is there a way to find the index of minItem.difference in my tideArray ? (so, the result here should be index = 1 )
I've tried tideArray.indexOf(minItem.difference)
but the output is -1, so the index wasn't found...
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Hmm I must have explain badly what I wanted.
I'm looking for the index number and not the value of "difference" or "tide".
So, in the example, I'd like to output "1" (as it's the second object in the array that is selected)
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index_min is that index number.