$sql = "INSERT INTO order SET
product ='" . $product . "',
size='" . $size . "',
color='" . $color . "',
quantity = '" . $quan . "',
I believe there are other more elegant ways to do this, as
well.
--
Murray --- ICQ 71997575
Adobe Community Expert
(If you *MUST* email me, don't LAUGH when you do so!)
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"beatzMalone" <webforumsuser@macromedia.com> wrote in
message
news:ghbiup$5s3$1@forums.macromedia.com...
> Ok guys im new to php mysql and i'm trying to insert
some form information
> in
> my database. Im using a script from sitepoint in which i
went through the
> tutorial did some experiments of my own and it
worked....
>
> but now i'm getting this error which i cant figure
out....
>
> Error placing order: You have an error in your SQL
syntax; check the
> manual
> that corresponds to your MySQL server version for the
right syntax to use
> near
> 'order SET product ='1', size='medium', color='',
quantity = '1' at line 1
>
> here is the page
>
http://vaughntucker.com/imagecon/hats.php
>
> and this is the script
> <?php
> //default page display
> //connect to database
> $dbcnx = @mysql_connect('p3nl41mysql7.secureserver.net',
'imagecon',
> 'Dub*boss_1');
> if (!$dbcnx) {
> echo '<p> Unable to connect to the '. 'database
server at this
> time.</p>';
> exit();
>
> }
>
> //select database
> if (!@mysql_select_db('imagecon')) {
> exit('<p>Unable to locate the ' .
> 'database at this time.</p>');
> }
>
> //Mysql query add joke
> if (isset($_POST['submit'])) {
> $product = 1;
> $size = $_POST['size'];
> $color = $_POST['color'];
> $quan = $_POST['quantity'];
> $sql = "INSERT INTO order SET
> product ='$product',
> size='$size',
> color='$color',
> quantity = '$quan',
> date = CURDATE()";
> }else{
> echo 'No data submited';
>
> }
> if (@mysql_query($sql)) {
> echo '<p>Your order has been submited.</p>';
> } else {
> echo '<p>Error placing order: ' .
> mysql_error() . '</p>';
> }
>
>
>
> ?>
>
> thanks in advance
>