Participating Frequently

Answered

Adjust varying lengths of line at once.

Forum|Forum|5 years ago
May 2, 2020
6 replies
1840 views

I am working on a project with topographic lines. Each line has varying space between them but they all increase by a height of 20mm (after I'm done they're vertically aligned to the bottom of the artboard). The lines on the left are an example of the ones that have been completed. Is there a way I adjust the length of all the lines at once with a constant increase in length?

Thanks!

This topic has been closed for replies.

Correct answer pixxxelschubser

Hi @wyatts93859812,

do you mean something like that?

The main "problem" is the basic structure of the script. Ultimately, only two loops are required:

// https://community.adobe.com/t5/illustrator/adjust-varying-lengths-of-line-at-once/td-p/11099361?page=1
// resize_increase_height_based_on_xPosition.jsx
// regard pixxxelschubser  03. März 2020

////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// required: opened document, only lines with the same height on the active layer //
// all paths are ungrouped and simple paths (lines)                                                      //
// no selection needed                                                                                                        //
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

main();
app.redraw();
alert("Done");

function main() {
var aDoc = app.activeDocument;
var Pths = aDoc.activeLayer.pathItems;
var len = Pths.length;
var list = new Array ();
var toMM = 2.83464567;
var Pth, item, factor, inc;

inc = prompt ("Please enter the value of increment (mm)", 2, "Increment");
if (inc == null) { return; }
if (inc.match(/[0-9]+/) == null) { return;}
inc = inc*1;

for (i = 0; i < len; i++) {
    Pth = new Array (2);
    Pth[0] = Pths[i].left;
    Pth[1] = Pths[i];
    list.push(Pth);
    }

list.sort();

for (k = len-1; k >= 0 ; k--) {
    item = list[k][1];
    factor = (item.height +inc*toMM*k)*100/item.height;    
    list[k][1].resize( 100, factor, true, true, true, true, 100, Transformation.CENTER );
    }
};

Before:

During:

Result:

If that works for you

have fun

😉

Jacob Bugge

Community Expert

For my part you are welcome, Wyatt.

Scripts are almost always easier (for the lucky one that can use it without having to create it).

We are very lucky to have scripter friends, such as Hans-Jürgen and Carlos.

pixxxelschubser

Correct answer

Community Expert

Hi @wyatts93859812,

do you mean something like that?

The main "problem" is the basic structure of the script. Ultimately, only two loops are required:

// https://community.adobe.com/t5/illustrator/adjust-varying-lengths-of-line-at-once/td-p/11099361?page=1
// resize_increase_height_based_on_xPosition.jsx
// regard pixxxelschubser  03. März 2020

////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// required: opened document, only lines with the same height on the active layer //
// all paths are ungrouped and simple paths (lines)                                                      //
// no selection needed                                                                                                        //
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

main();
app.redraw();
alert("Done");

function main() {
var aDoc = app.activeDocument;
var Pths = aDoc.activeLayer.pathItems;
var len = Pths.length;
var list = new Array ();
var toMM = 2.83464567;
var Pth, item, factor, inc;

inc = prompt ("Please enter the value of increment (mm)", 2, "Increment");
if (inc == null) { return; }
if (inc.match(/[0-9]+/) == null) { return;}
inc = inc*1;

for (i = 0; i < len; i++) {
    Pth = new Array (2);
    Pth[0] = Pths[i].left;
    Pth[1] = Pths[i];
    list.push(Pth);
    }

list.sort();

for (k = len-1; k >= 0 ; k--) {
    item = list[k][1];
    factor = (item.height +inc*toMM*k)*100/item.height;    
    list[k][1].resize( 100, factor, true, true, true, true, 100, Transformation.CENTER );
    }
};

Before:

During:

Result:

If that works for you

have fun

😉

W

wyatts93859812Author

Participating Frequently

Thank you, this will save me to much time!

CarlosCanto

Community Expert

it could be scripted, I'm not sure what the requirement is.

Jacob Bugge

Community Expert

wyatts,

Can you reverse the order of how you build the lines?

As far as I can see you create short lines and distribute them at varying distances, and then you wish to increase their lengths linearly.

If you can create them at different lengths and then place them at varying distances, it is much easier because you can start by create lines at linearly increasing lengths with a simple Blend, expand the Blend, and then distribute the lines as desired.