Back to the speedometer and hash/tick marks

[Jber505]

Soooo... I'm back! and here is my problem:

I've gone over the prior discussions because I simply cannot figure out why this particular speedometer's hash marks are not aligning correctly.  Here is what I'm doing:(the large hash marks on the speedometer equal 11 and there is a 90 degree gap at the bottom of the speedometer, there are 21 small hash marks).

I create the outer circle, then the inner circle (the inner circle isn't actually needed for the moment);

on a new layer I create the large hash mark;

I select the outer circle and the large hash mark and copy them to another layer

I transform them: 360-90/11 = 24.55 with 10 copies (see top circle)

then, I copy the original outer circle and the original large hash mark to a new layer and adjust the stroke weight to represent the small hash mark

then I transform 360-90/21 = 12.86 with 20 copies (see middle circle)

and you can see my bottom circle that the two sets of hash marks do not align properly.  What am I doing wrong?

Thanks,

Jber

[Jacob Bugge · Accepted solution]

Jber,

You should use (360-90)/10 and (360-90)/20, because the first one counts as number 0, and there are 10/20 intervals, in other words 270/10 = 27 and 270/20 = 13.5 so two small ones correspond to on big one (intervals). The gap is also much more than 90 degrees (about 114.5 degrees).

The reason for the strange(ness of the) misalignment is that the division by 21 (20+1) is only half as much off as is the division by 11 (10+1).

You need to rotate to have the 90 degrees gap at the bottom of course.

[Jber505]

PERFECT! wow, such a simple fix and I just couldn't see it.  Thank you very very much!

[Jacob Bugge]

You are welcome, Jber.

Your challenging threads are always a pleasure.

[Jacob Bugge]

Jber,

Unless of course you actually have two small tick marks for dividing each interval of big tick marks into three. In that case you need 31 small ones, the 11 coinciding with/hidden by the 11 big ones, and you should use (360-90)/30 = 270/30 = 9, so each big one corresponds to three small ones.