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Bulk aligning and sorting a selection of objects?

Community Beginner ,
Jan 16, 2023 Jan 16, 2023

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I'm looking to left align a selection of objects which have been scaled as part of a script then distribute the spacing at a set amount of 14.1732p

 

Is there a way to rearrange the selection into columns of objects if over a certain amount?

eg. rows of 7?

 

Below is the code from another thread adjust to individually re-size the objects proportionally if over a max dimension.

 

function scaleDownProportionally(item, maxSize) {
var W = item.width,
H = item.height,
MW = maxSize.W,
MH = maxSize.H,
factor = W / H > MW / MH ? MW / W * 100 : MH / H * 100;

if (W > MW || H > MH) {
item.resize(factor, factor);
}
}

for (var i = 0; i < app.selection.length; i++) {
scaleDownProportionally(app.selection[i], {W: 853.228, H: 127.559});
}

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correct answers 1 Correct answer

Guide , Jan 16, 2023 Jan 16, 2023

To resize about the left, change

item.resize(factor, factor);

in your script to

item.resize(factor, factor, undefined, undefined, undefined, undefined, undefined, Transformation.LEFT);

 

To rearrange the column into columns each with seven rows, add to the end of your script

rearrange(5 /*gap between columns (mm)*/,
          7 /*number of rows in column*/);
function rearrange(gap, n) {
    var a = [];
    for (var i = 0; i < app.selection.length; i++) {
        a.push(app.selection[i]);
    }
    a.s
...

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Guide ,
Jan 16, 2023 Jan 16, 2023

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Can you show screenshots of a before and after?  

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Community Beginner ,
Jan 16, 2023 Jan 16, 2023

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Thanks for the reply, I've attached a screenshot that hopefully helps

 

Screenshot 2023-01-16 at 14.01.08.png

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Guide ,
Jan 16, 2023 Jan 16, 2023

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To resize about the left, change

item.resize(factor, factor);

in your script to

item.resize(factor, factor, undefined, undefined, undefined, undefined, undefined, Transformation.LEFT);

 

To rearrange the column into columns each with seven rows, add to the end of your script

rearrange(5 /*gap between columns (mm)*/,
          7 /*number of rows in column*/);
function rearrange(gap, n) {
    var a = [];
    for (var i = 0; i < app.selection.length; i++) {
        a.push(app.selection[i]);
    }
    a.sort(function(a, b) {return b.width - a.width;});
    var w = a[0].width;
    a.sort(function(a, b) {return b.top - a.top;});
    for (var i = n; i < a.length; i++) {
        a[i].position = [a[i - n].position[0] + w + gap * 2.835, 
                         a[i - n].position[1]];
    }
}

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Community Beginner ,
Jan 17, 2023 Jan 17, 2023

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This works perfectly, thank you so much. 

Is there a way to organise distribute the spacing between the items in each column by a set amount as well?

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Guide ,
Jan 17, 2023 Jan 17, 2023

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Replace the preceding function with this

rearrange(10 /*gap between rows (mm)*/,
          5 /*gap between columns (mm)*/,
          7 /*number of rows in column*/);
function rearrange(gap1, gap2, n) {
    var a = [];
    for (var i = 0; i < app.selection.length; i++) {
        a.push(app.selection[i]);
    }
    a.sort(function(a, b) {return b.width - a.width;});
    var w = a[0].width;
    a.sort(function(a, b) {return b.top - a.top;});
    for (var i = 1; i < a.length; i++) {
        if (i < n) {
            a[i].position = [
                a[i].position[0],
                a[i - 1].position[1] - a[i - 1].height - gap1 * 2.835
            ];
        } else {
            a[i].position = [
                a[i - n].position[0] + w + gap2 * 2.835, 
                a[i - n].position[1]
            ];
        }
    }
}

 

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Community Beginner ,
Jan 18, 2023 Jan 18, 2023

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Thank you very much femkeblanco.

This works but is currently only applying the spacing to the first column and not subsequent columns?
Is it also possible to have a max number of columns before starting a new batch? I realised that with long lists the process takes it off the workspace. For example 6 columns before starting a new set underneath with a wider gap.

Alternatively I could set the amount of rows higher and split manually afterwards.
Thanks again!

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Guide ,
Jan 18, 2023 Jan 18, 2023

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The above function works as expected for me (shown below).  What are the circumstances in which it is not working for you?  The function is modified below to rearrange the original column into sets.  In the example below, a set is 3 columns. 

 

 

 

 

rearrange(10 /*gap between rows (mm)*/,
          5  /*gap between columns (mm)*/,
          7  /*number of rows in column*/,
          3  /*number of columns per set*/);
function rearrange(gap1, gap2, n, m) {
    var start = counter = 0;
    var a = [];
    for (var i = 0; i < app.selection.length; i++) {
        a.push(app.selection[i]);
    }
    a.sort(function(a, b) {return b.width - a.width;});
    var w = a[0].width;
    a.sort(function(a, b) {return b.top - a.top;});
    for (var i = 0; i < a.length; i++) {
        if (i == start) {
            if (i == 0) {
                a[i].position = [
                    a[0].position[0],
                    a[0].position[1]
                ];
            } else {
                a[i].position = [
                    a[0].position[0],
                    a[i - 1].position[1] - a[i - 1].height - gap1 * 2.835 * 2
                    // gap between sets twice gap between rows
                ];
            }
        } else if (i < start + n) {
            a[i].position = [
                a[0].position[0],
                a[i - 1].position[1] - a[i - 1].height - gap1 * 2.835
            ];
        } else {
            a[i].position = [
                a[i - n].position[0] + w + gap2 * 2.835, 
                a[i - n].position[1]
            ];
        }
        counter++;
        if (counter == n * m) {
            start += counter;
            counter = 0;
        }
    }
}

 

 

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Community Beginner ,
Jan 19, 2023 Jan 19, 2023

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Thanks again, this works great with the sets.

It seems to be when there is a variance in the length of the word in the list, I've just tried with a matching word and it works great.

I've attached an image of the output with varying word length.

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Community Beginner ,
Jan 27, 2023 Jan 27, 2023

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With my attempts I haven't been able to make sure the spacing is arranged post sorting into columns and sets?

Any ideas with this? @femkeblanco 

Thanks again for all the help

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Guide ,
Jan 27, 2023 Jan 27, 2023

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Sorry.  I don't know what the problem you are having is.  Could you expound, preferably with screenshots? 

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Community Beginner ,
Jan 30, 2023 Jan 30, 2023

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Thanks for taking a look for me. 
I've realised that it's only happened when the amount of objects in a row is anything other than 7, in these cases the objects are not aligned or spaced out correctly. I've attached a screenshot to show how it looks with the number of rows set to 8.

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Guide ,
Jan 30, 2023 Jan 30, 2023

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Unfortunately, I think we have reached a limitation of the above script.  This arranges the first column first, so it doesn't account for variable heights in the succeeding columns.  I can arrange the first column based on a max height, but the result will not look tidy.  (This is compounded by the fact that the arranging is based on the text frame top position, not base line.)  You could try (a) increasing the first argument (gap between rows) until you get an acceptable result (with no overlap) or (b) starting over by posting a new question. 

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Community Beginner ,
Jan 31, 2023 Jan 31, 2023

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Thanks for the response! I think in most cases 7 will work perfectly and it's easy enough to align in other situation.

Again, thanks for all your help with this.

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