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Different photo resolution reading between Illustrator and Acrobat

Explorer ,
Dec 09, 2021 Dec 09, 2021

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Hi everyone,

I was just curious as to why this photo in a PDF gives me a reading PPI of 296x278 PPI in Illustrator vs 300x300 PPI when I view it using the object inspector in Acrobat. As you can see it is placed in a clipping mask (I have it selected with the direct selection tool) and the photo was rotated--I assume that has something to do with it. My understanding is that you are not descreasing the size of the photo, just cropping it with clipping mask...so I would think the effective resolution would not change and it would read the same in both programs. If someone could enlighten me, I would greatly appreciate it!

 

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correct answers 1 Correct answer

Community Expert , Dec 09, 2021 Dec 09, 2021

It is because of the rotation, and it's because of how Illustrator determines the effective PPI.

Illustrator measures the PPI on horizontal and vertical axis only, not on an angle, so a photo rotated even a little bit becomes a bit wider from corner to corner, and that ratio affects the apparent PPI. It throws people off, but in the end, nothing has happened to your photo.

Acrobat, on the other hand, sees it differently as it's reading the PPI for the photo itself apart from the rotation. 

Screen Shot 2021-12-09 at 11.53.45 AM.png

If i

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Community Expert ,
Dec 09, 2021 Dec 09, 2021

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It is because of the rotation, and it's because of how Illustrator determines the effective PPI.

Illustrator measures the PPI on horizontal and vertical axis only, not on an angle, so a photo rotated even a little bit becomes a bit wider from corner to corner, and that ratio affects the apparent PPI. It throws people off, but in the end, nothing has happened to your photo.

Acrobat, on the other hand, sees it differently as it's reading the PPI for the photo itself apart from the rotation. 

Screen Shot 2021-12-09 at 11.53.45 AM.png

If it makes you feel any better, this has come up as a feature request many times to rethink how this works. I don't have a link to the User Voice item, but if you do a search, add your vote to the idea

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Community Expert ,
Dec 09, 2021 Dec 09, 2021

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My example was a square, but in your case, your photo is a rectangle so the increase in x/y dimensions are different when rotated, hence your effective PPI reading is two different numbers, the larger number is the horizontal followed by the vertical determination.

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Community Expert ,
Dec 09, 2021 Dec 09, 2021

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