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I need a script that groups filled paths by color for paintings by numbers.

New Here ,
Aug 25, 2020 Aug 25, 2020

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Hello folks,

In a recent post (https://community.adobe.com/t5/illustrator/script-insert-text-number-in-the-middle-of-visible-bounds...) I was reading on the following matter: the author uploaded a script that groups filled paths by color for paintings by numbers. However, when I tried to apply it to my Illustrator, it didn't work. Instead of showing different numbers in each field, I only get one and the same number.

 

I would appreciate it if someone could help me with a new, working script. I am also willing to pay for one.

 

Cheers.

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Draw and design , Feature request , Scripting , Tools

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correct answers 1 Correct answer

Community Expert , Aug 25, 2020 Aug 25, 2020

Hi,

Another version of the script. This is handling just pathItems and CMYK colors.  You can test it for simple sneario. This is not final and clean version. Code reference from the same link that you have shared

 

 

 

#target illustrator
    
var doc = app.activeDocument;
function main() {
    var _pageItems = doc.pageItems;
    var _layersCollection = [];
    for (var p = 0; p < _pageItems.length; p++) {
        collectItemsBasedOnColors(_pageItems[p], _layersCollection);
    }
    lays = doc.
...

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Community Expert ,
Aug 25, 2020 Aug 25, 2020

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Hi,

Another version of the script. This is handling just pathItems and CMYK colors.  You can test it for simple sneario. This is not final and clean version. Code reference from the same link that you have shared

 

 

 

#target illustrator
    
var doc = app.activeDocument;
function main() {
    var _pageItems = doc.pageItems;
    var _layersCollection = [];
    for (var p = 0; p < _pageItems.length; p++) {
        collectItemsBasedOnColors(_pageItems[p], _layersCollection);
    }
    lays = doc.layers;
    WORK_LAY = lays.add();
    NUM_LAY = lays.add();

    for (var l = 0; l < _layersCollection.length; l++) {
        process(_layersCollection[l].pathItems, false, (l + 1));
    }
}

function process(items, isCompound, _num) {
    var j = 0,
        b, xy, s, p, op;

    for (; j < items.length; j++) {
        // process each pathItem
        op = items[j];
        // add stroke
        if (isCompound) {
            strokeComPath(op);
        } else {
            !op.closed && op.closed = true;
            op.filled = false;
            op.stroked = true;
        };
        b = getCenterBounds(op);
        xy = [b[0] + (b[2] - b[0]) / 2, b[1] + (b[3] - b[1]) / 2];
        s = (
            Math.min(op.height, op.width) < 20 ||
            (op.area && Math.abs(op.area) < 150)
        ) ? 4 : 6; // adjust font size for small area paths.
        add_nums(_num, xy, s);
    }
}

function collectItemsBasedOnColors(myCurrentObject, _layersCollection) {
    var myLayerName = "Unknown";
    if (myCurrentObject.typename == "PathItem") {
        if (myCurrentObject.filled == true) {
            if (myCurrentObject.fillColor == "[CMYKColor]") {
                myLayerName = "CMYK: " + Math.round(myCurrentObject.fillColor.cyan) + "," + Math.round(myCurrentObject.fillColor.magenta) + "," + Math.round(myCurrentObject.fillColor.yellow) + "," + Math.round(myCurrentObject.fillColor.black);
            }
        }
        try {
            var _layer = doc.layers.getByName(myLayerName);
            myCurrentObject.move(_layer, ElementPlacement.PLACEATBEGINNING);
        }

        catch (e) {
            var _layer = doc.layers.add()
            _layer.name = myLayerName
            myCurrentObject.move(_layer, ElementPlacement.PLACEATBEGINNING);
            _layersCollection.push(_layer);
        }
    }
}

function getCenterBounds(op) {
    var originalMinSize = getMinVisibleSize(op.visibleBounds);

    var p = applyOffset(op, false);

    if (getMinVisibleSize(p.visibleBounds) > originalMinSize) {
        // in some cases, path p becomes larger for some unknown reason
        p.remove();
        p = applyOffset(op, true);
    }

    var b = p.visibleBounds;

    if (getMinVisibleSize(b) > 10) {
        activeDocument.selection = [p];
        executeMenuCommand("expandStyle");
        p = activeDocument.selection[0];
        if (p.typename == "CompoundPathItem") {
            b = findBestBounds(op, p);
        }
    }

    p.remove();
    return b;
}

function getMinVisibleSize(b) {
    var s = Math.min(b[2] - b[0], b[1] - b[3]);
    return Math.abs(s);
}

function add_nums(n, xy, s) {
    var txt = NUM_LAY.textFrames.add();

    txt.contents = n;
    txt.textRange.justification = Justification.CENTER;
    txt.textRange.characterAttributes.size = s;
    txt.position = [xy[0] - txt.width / 2, xy[1] + txt.height / 2];
}


function applyOffset(op, checkBounds) {
    var p = op.duplicate(WORK_LAY, ElementPlacement.PLACEATBEGINNING),
        // offset value the small the better, but meantime more slow. 
        offset = function () {
            var minsize = Math.min(p.width, p.height);
            if (minsize >= 50) {
                return '-1'
            } else if (20 < minsize && minsize < 50) {
                return '-0.5'
            } else {
                return '-0.2' // 0.2 * 2 (both side ) * 50 (Times) = 20
            }
        },
        xmlstring = '<LiveEffect name="Adobe Offset Path"><Dict data="I jntp 2 R mlim 4 R ofst #offset"/></LiveEffect>'
            .replace('#offset', offset()),
        TIMES = 100; // if shapes are too large, should increase the value.

    if (checkBounds) {
        // check its size only if it needs, because it's too slow
        while (TIMES-- && getMinVisibleSize(p.visibleBounds) > 3) p.applyEffect(xmlstring);
    } else {
        while (TIMES--) p.applyEffect(xmlstring);
    }
    return p;
}

function getGeometricCenter(p) {
    var b = p.geometricBounds;
    return [(b[0] + b[2]) / 2, (b[1] + b[3]) / 2];
}

// returns square of distance between p1 and p2
function getDist2(p1, p2) {
    return Math.pow(p1[0] + p2[0], 2) + Math.pow(p1[1] + p2[1], 2);
}

// returns visibleBounds of a path in a compoundPath p
// which is closest to center of the original path op
function findBestBounds(op, p) {
    var opc = getGeometricCenter(op);
    var idx = 0,
        d;
    var minD = getDist2(opc, getGeometricCenter(p.pathItems[0]));
    for (var i = 0, iEnd = p.pathItems.length; i < iEnd; i++) {
        d = getDist2(opc, getGeometricCenter(p.pathItems[i]));
        if (d < minD) {
            minD = d;
            idx = i;
        }
    }
    return p.pathItems[idx].visibleBounds;
}

main();

 

 

 

Running with attached sample file. Ofcourse more can be done to handle other scenarios.

Sample File 

Best regards

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New Here ,
Aug 25, 2020 Aug 25, 2020

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qqqqq.jpg

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Community Expert ,
Aug 25, 2020 Aug 25, 2020

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Just updated the code, keep following line

var doc = app.activeDocument;

out the main() function.

Best regards

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New Here ,
Aug 25, 2020 Aug 25, 2020

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When I try the updated code the same error pops-up as before. 

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Community Expert ,
Aug 25, 2020 Aug 25, 2020

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How are you executing the code? Are you using extended toolkit?

Best regards

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New Here ,
Aug 25, 2020 Aug 25, 2020

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I load the code directly from illustrator.01.jpg

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Community Expert ,
Aug 25, 2020 Aug 25, 2020

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I tried in this way as well, and it is running successfully.

Did you save your code with .jsx extension?

Best regards

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Guide ,
Aug 25, 2020 Aug 25, 2020

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I tried the script on this thread in CS6 and it seems to be working fine for me.  (Thank you, Charu.)

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Community Expert ,
Aug 25, 2020 Aug 25, 2020

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Thanks femkeblanco  for confirming 🙂

Best regards

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New Here ,
Aug 26, 2020 Aug 26, 2020

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I would like the script to show the numbers from 1 to 9 and then to start to show letters: "A,B,C..." and so on. So, for example - 1,2,3,4,5,6,7,8,9,A,B,C,D...etc. 

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New Here ,
Aug 28, 2020 Aug 28, 2020

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Hello folks,

Can someone of you please help me with a code I need for Illustrator? 

 

I'm working with paintings by numbers and would like the script to show the numbers from 1 to 9 and then to start to show letters: "A,B,C..." and so on. So, for example - 1,2,3,4,5,6,7,8,9,A,B,C,D...etc. 

 

Any help would greatly be appreciated.

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Guide ,
Aug 28, 2020 Aug 28, 2020

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Replace the line (which is line 100 in the above script)

txt.contents = n;

with these two lines

var x = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"];
txt.contents = x[n];

 

The script will fail if you go beyond "Z".

 

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New Here ,
Aug 29, 2020 Aug 29, 2020

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Thank you very nice.

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New Here ,
Jul 14, 2021 Jul 14, 2021

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hi there please could I have the link to download this script also. it would be much appreciated

 

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Community Expert ,
Jul 14, 2021 Jul 14, 2021

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there's no download link, the script is posted here in response #1 by Charu. You have to copy/paste in a blank text file and save it with any name, but change the extension to jsx

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New Here ,
Feb 04, 2023 Feb 04, 2023

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Hello!

when one shape is inside another, the script puts the number into the inner shape three times.

How to fix it?

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New Here ,
Apr 25, 2022 Apr 25, 2022

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Hi all folks,

I get the following error, does anyone knows how can I fix it?

Error 1200: an illustrator error occurred: 1246458189 ('MRAP')

Line:128

-> while (TIMES--) p.applyEffect(xmlstring);

Thank you in advance 

Captura de Pantalla 2022-04-25 a la(s) 13.29.32.png

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Enthusiast ,
Feb 06, 2023 Feb 06, 2023

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New Here ,
Feb 06, 2023 Feb 06, 2023

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It's not working with compound paths 😞

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Enthusiast ,
Apr 30, 2023 Apr 30, 2023

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It was never intended to. Compound Paths can have multiple fills within their children paths, and you wouldn't be able to group those children paths with other paths without breaking the compound.

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Community Beginner ,
Feb 15, 2024 Feb 15, 2024

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LATEST

Hello. What can be done in this script to put more than one number depending on the area of the object?

For example like this!Test.jpg

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