New value for property position

[Steven Charles-Charlery]

Hello, hello

I have a problem with property position about pathItem in Illustrator, in Javascript I can write : object.position[0] = newValue and position from object change.

But no with illustrator objects, I can't use pathItem.position[0] = newValue because position from pathItem don't change.

I try a test, I share with you code :

---------

var x = app.activeDocument.activeLayer.pathItems["coucou"]

$.writeln("First value : " + x.position) //Result : First value : 17,-11

x.position[0] = 10

x.position[1] = 20

$.writeln("New value : " + x.position) //Result: New value : 17,-11

---------

Thank you, thank you for your help and sorry for my bad english

[Disposition_Dev]

try this:

var x = app.activeDocument.activeLayer.pathItems["coucou"]

$.writeln("First value : " + x.position) //Result : First value : 17,-11

x.position = [10,20];

$.writeln("New value : " + x.position) //Result: New value : 17,-11

[Steven Charles-Charlery]

Hello, thank you for your answer.

I can do this but I want just modify one value without write all array.

When I write :

---

var x = [1, 2, 3];

x[0] = 10;

$.writeln(x[0]) //Result : 10

---

I want do it with property position without write all array.

It's work for object JavaScript but no for Illustrator object.

[CarlosCanto · Accepted solution]

that's how it works, position property takes a pair of values. You can't assign each value individually.

try this instead, if you want to change only the x position

var left = 10;

var top = x.position[1];

x.position = [left, top];

[Steven Charles-Charlery]

Ok, thus impossible with property position, thank you because i don't saw it in documentation 😕

It's same for all array about illustrator object and illustrator properties or just for property position ?

[Disposition_Dev]

No, it's not impossible. Just like carlos mentioned, you simply have to feed it an array. but you don't need to manually populate all of the elements of the array.. you can pull one of the values right out of the existing position array.

x.position = [10,x.position[1]];

[Steven Charles-Charlery]

Yes, i do it, thank you.

Just, I don't undestand why I can just write pathItem.position[0] = newValue

Thx to take time for answer me

[renél80416020]

Salut !

La vie est dure...

// JavaScript Doc
  var docRef = documents.add( DocumentColorSpace.CMYK,600,800);
      docRef.rulerOrigin = [0,0];
      ogjRect = docRef.pathItems.rectangle(750,20,100,100);
      redraw();
      alert(ogjRect.position);
      var dx = 5;
      for (var i = 1; i < 50; i++) {
          ogjRect.position = [20+dx*i,750];
          redraw();
      }
      alert(ogjRect.position)
      for (var j = 1; j < 50; j++) {
          ogjRect.position = [ogjRect.position[0]-dx,ogjRect.position[1]];
          redraw();
      }
      alert(ogjRect.position)

de elleere

position Array de 2 nombres

[Steven Charles-Charlery]

Ah vous parlez français, c'est cool.

Sinon, j'ai fais a peu près ça pour contourner le problème.

C'est dommage que le fait que la propriété position ne prend qu'un couple de valeurs, ne soit pas écrit dans la documentation ExtendScript.

[Disposition_Dev]

function test()

{

     var docRef = app.activeDocument;

     var path = docRef.pageItems[0];

     path.left = 10;

     path.top = 20;

}

test();

[Steven Charles-Charlery]

Thank you I tried left and top but left and top include stroke weight @@