RegExp for multiple search items?

[subieguy2]

So I am wanting to find a part number in a document. There could be several part numbers. Thanks to some of the users here I have code that currently looks like this....

#target illustrator
function changeData() {
    function processDoc(doc) {
        // OLD PART NUMBER
        var oldPart = /111-1111/gi;
        // NEW PART NUMBER
        var replacePart = "111-1111",
            result;
        var allText = doc.textFrames;
        // SEARCH AND CHANGE LOOP FOR PART #
        while (result = oldPart.exec(allText.contents)) {
            try {
                aCon = allText.characters[result.index];
                aCon.length = result[0].length;
                aCon.contents = replacePart;
            } catch (e) {};
        }
        // SCAN THRU ALL OPEN DOCUMENTS
        for (var i = 0; i < app.documents.length; i++) {
            app.documents.activate();
            processDoc(app.activeDocument);
        };
    };
  changeData();

Now please excuse my lack of knowledge but I was wondering if it is possible to do a list search and list change. I know this isn't the syntax to use but just to get the point across....

// OLD PART NUMBER
var oldPart = /111-1111 || 222-2222 || 333-3333/gi;
// NEW PART NUMBER
var replacePart = "444-4444 || 555-555 || 666-6666", result;

So if part 111-1111 is found it would change it to 444-4444. if part 222-2222 is found it would change it to 555-5555. if part 333-3333 is found it would change it to 666-6666.

Can anyone explain how to do this within my function??

Thanks in advance!

[Silly-V]

Looks like you can just put your old part numbers and new ones into 2 arrays and go through them.

[subieguy2]

Ok so how do you apply an array to a regexp?

[subieguy2]

Ok so I understand how to search for multiple items in a regexp...but how do i make it match to an array position for the new part or results???

#target illustrator  
function changeData() {  
    function processDoc(doc) {  
        // OLD PART NUMBER  
        var oldPart = /111-1111|222-2222|333-3333/gi;  
        // NEW PART NUMBER  
        var replacePart = "111-1111", result;  
        var allText = doc.textFrames;   
        // SEARCH AND CHANGE LOOP FOR PART #  
        while (result = oldPart.exec(allText.contents)) {  
            try {  
                aCon = allText.characters[result.index];  
                aCon.length = result[0].length;  
                aCon.contents = replacePart;  
            } catch (e) {};  
        }  
        // SCAN THRU ALL OPEN DOCUMENTS  
        for (var i = 0; i < app.documents.length; i++) {  
            app.documents.activate();  
            processDoc(app.activeDocument);  
        };  
    };  
changeData();

[Silly-V]

Just use a simple array and make the 'process all documents' loop be inside of a loop that goes through your array of items to replace.

var replaceThese = ["111-1111", "222-2222"];

var withThese = ["333-3333", "555-5555"];

for(var i=0; i<replaceThese.length; i++){

     for (var j = 0; j < app.documents.length; j++) {  

       app.documents[j].activate();  

       processDoc(app.activeDocument, replaceThese, withThese);  

     };

};

Of course you will have to modify your processDoc function to accept the replacee with the replacer as 2 additional arguments.

[subieguy2]

I understand what you are saying and thank you for that. However I guess I didn't give all the information....sorry about that.

The part number I am looking to replace is within a sentence (meaning it isn't in a text frame by itself).

Plus I also need to keep the formatting.

Here is an example of what the document would contain.

PART NUMBER: 111-1111, CHANGE: 05, VERSION: -    (All of that is in one text frame)

PART NUMBER: 222-2222, CHANGE: 01, VERSION: HE   (All of that is in one text frame)

Both of the above text frames could be on one document....or could be on separate documents.

[Silly-V]

Ya so you would need to change up your processDoc function to go something like this:

    function processDoc(doc, oldTxt, newTxt) {   

        // OLD PART NUMBER   

        var oldPart = new RegExp(oldTxt, "gi");   

        // NEW PART NUMBER   

        var replacePart = newTxt, result; 

[subieguy2]

I'm sorry Silly-V​.... I appreciate your help but this is more advanced than I know how to put together. I'm new to regexp and I don't usually do functions.... lol

So basically what I am saying is I am a graphic designer and suck at programming.

[Silly-V]

Don't worry you don't suck, you can do it, you have the awesome powers of greatness and you can overcome any obstacle!