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(?<=“).*?(?=“)
is a grep expression to find text inside quotation marks.
but how to delimit the search to define exactly a number of words inside the curly quotes?
for example, detect only quotations that have more than n words? 50, for example?
this comes as it is a publishing practice to style those «block quotations» and get broken off without quotation marks.
thanks
Did you try Laubender 12 ?
If you copy/paste the expressions you have to look carefully after the curley quotes in the expression.
Best you type the expression yourself. Without using straight quotes.
I only tested with English text. Not e.g. German text where the quotes for opening and closing are very different.
The only GREP expression working straight for me is:
Laubender 12
“([()[\]]?\<[^“]+\>[,;:!?.…()[\]\h]*){21}”
Obi-wan 15 is also working, but first I had to change the quotes to that:
“(([^ “]
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The issue here is that you'll have to account for any types of spaces and punctuations that may occur, while limiting the number of WORDS to 50. In theory, it's probably doable...it's just above my "pay grade," as they say.