Hi @Kunal98C6, this was a fun question! I've written a script to do this. Please give it a try and let me know how it goes.
- Mark
/**
* @file Add Table Random Letters.js
*
* Adds random letters to empty table cells.
* Chooses more common letters more often.
*
* Note: you can run script again and again
* until you are happy - it shouldn't overwrite
* your original text. It stores the empty
* cell coordinates in a label so it knows
* where to re-populate.
*
* @author m1b
* @version 2024-07-25
* @discussion https://community.adobe.com/t5/indesign-discussions/indesign-table-script/m-p/14758845
*/
function main() {
var settings = {
// these are in order of most common first
letters: 'ETAOINSHRDLUCMFYWGPBVKXQJZ',
};
if (0 === app.documents.length)
return alert('Please open a document and try again.');
var doc = app.activeDocument,
table = getTable(doc.selection);
if (!table)
return alert('Please select a table and try again.');
var letters = settings.letters;
// first collect empty cells
var emptyCells = table.extractLabel('emptyCells') || [];
if (0 == emptyCells.length) {
for (var i = 0; i < table.cells.length; i++)
if ('' == table.cells[i].contents)
emptyCells.push(table.cells[i].name);
table.insertLabel('emptyCells', String(emptyCells));
}
else if ('String' === emptyCells.constructor.name) {
emptyCells = emptyCells.split(',');
}
for (var i = 0, xy, cell; i < emptyCells.length; i++) {
xy = emptyCells[i].split(':');
cell = table.rows[Number(xy[1])].cells[Number(xy[0])];
if (!cell.isValid)
continue;
cell.contents = letters[weightedRandom(0, letters.length - 1, 5, 1)];
}
}
app.doScript(main, ScriptLanguage.JAVASCRIPT, undefined, UndoModes.ENTIRE_SCRIPT, 'Add Table Random Letters');
/**
* Attempts to return a Table, given an object.
* @author m1b
* @version 2023-02-06
* @param {InsertionPoint|Text|Cells|Table|TextFrame} obj - an object related to a Cell.
* @returns {Cell}
*/
function getTable(obj) {
if (obj == undefined)
return;
if ('Array' === obj.constructor.name) {
for (var i = 0, table; i < obj.length; i++) {
table = getTable(obj[i]);
if (table && table.isValid)
return table;
}
return;
}
if (obj.constructor.name == 'Cell')
return obj.parent;
if (obj.parent.constructor.name == 'Cell')
return obj.parent.parent;
if (
obj.hasOwnProperty('cells')
&& obj.cells.length > 0
)
return obj.cells[0].parent;
if (
obj.hasOwnProperty('tables')
&& 0 !== obj.tables.length
)
return obj.tables[0];
};
/**
* Returns a number between `min` and `max`,
* weighted by `minProbability` and `maxProbability`.
* If `minProbability` `maxProbability` are equal,
* then there is no weighting.
* @author m1b, from python code by Peter O. https://stackoverflow.com/questions/67225968/give-lower-values-a-higher-weight-in-a-randint-function/67226933#67226933
* @version 2023-12-27
* @param {Number} min - the lowest number you want.
* @param {Number} max - the highest number you want.
* @param {Number} minProbability - the likelihood of getting `min`.
* @param {Number} maxProbability - the likelihood of getting `max`.
*/
function weightedRandom(min, max, minProbability, maxProbability) {
if (undefined == min)
min = 0;
if (undefined == max)
max = 1;
if (max == min)
return min;
if (
undefined == minProbability
|| undefined == maxProbability
)
throw Error('weightedRandom: bad parameters.');
while (true) {
// get the highest weight
var highestWeight = Math.max(minProbability, maxProbability),
// generate a random integer in the interval min..max
r = Math.floor(Math.random() * (max - min + 1)) + min,
// calculate the weight for this integer
weight = minProbability + (maxProbability - minProbability) * ((r - min) / (max - min)),
// generate a random value between 0 and the highest weight
v = Math.random() * highestWeight;
// return r when v is less than the weigth
if (v < weight)
return r;
}
};
1
Reply
AdChoices