remove paragraph style error

[Johnwhite]

Hi experts,

My script like this:

var cDoc = app.activeDocument;
       myPara = cDoc.ParagraphStyle.name.match(/\(Note\)/,g);
        if (myPara.isValid){
        myPara.remove();
        }
        else exit;       

aim to remove paragraph style which name match (Note).

how can I make it work?

thanks

regard

John

[payalm68947498]

hi John ,

    you can remove paragraph style like this,

var cDoc = app.activeDocument;  
       myPara = cDoc.paragraphStyles.item("Note");  
        if (myPara.isValid){  
        myPara.remove();  
        }  
        else exit;  

[Laubender · Accepted solution]

Hi John,

check your variable named: myPara.

This would hold the result of the match if everything would be ok in that code line.

However it is not:

There is no property ParagraphStyle for a document.

Also check the regular expression. Best test something like that before with a string you are familiar with:

var s = "Before (Note) After";
s.match( /\(Note\)/,g); // will give an error: g is undefined.

You have to write g as a string. Sorry, I have to correct myself. See corrected code below:

Also note, that there could be more instances than one paragraph style name that could match.

If you want to check all paragraph styles loop the allParagraphStyles array of the document so that you can also see into paragraph styles in style groups.

Something like that should be robust enough:

var doc = app.activeDocument;
var paraStyles = doc.allParagraphStyles; // Returns an array;
// Array to store the ids of all matches:
var idsOfStylesToRemove = [];
// Loop the array to check every paragraph style name in the document:
for( var n=0; n<paraStyles.length; n++ )
{
    if( paraStyles.name.match( /\(Note\)/g ) )//EDITED
    { idsOfStylesToRemove[ idsOfStylesToRemove.length++ ] = paraStyles.id };
};
// Loop the results and remove every style there:
for( var n=0; n<idsOfStylesToRemove.length; n++ )
{ doc.paragraphStyles.itemByID( idsOfStylesToRemove ).remove() };

Regards,
Uwe

[Johnwhite]

Thank you Uwe

thank you so much.

John