removing multiple possible suffixes from linked files names js

[c.pfaffenbichler]

Good monday-morning!
I work on a Script that relinks images with ones that have been separated according to other print-conditions and carry some suffix to indicate this; to get it to recognize the correct ones I need to remove potential existing suffixes ("_lay" for example but also signifiers for other separations) from the linked images names.
I get this to work with either a series of »replaces« or a »for«-clause and an array of the possible suffixes, but Im only looking for a more elegant or simple way to do this in JavaScript.
So what would in Your valued opinions be the most concise way to remove a host of possible letter-combinations from a String?

Thanks for any advice
pfaffenbichler

[srakete]

hi christoph,
I had a simililar problem for adnumbers, that I solved with a regular expression.

String.prototype.getAdnumber = function () {
var reg = new RegExp("\\d+");//any Number at the beginning of the string
var myString = reg.exec(this);
return myString;
}

You need to find the correct expression for your needs.

Stefan

[c.pfaffenbichler]

Thanks, Stefan, and please forgive my late reply, but work has picked up the pace lately.
I hope I will be able to consider Your proposal more thoroughly sometime soon.

[Kasyan Servetsky]

Hi Christoph,

If suffixes are delimited by underscore, which used only once in a file name, then you can get rid of them in this way:

var myOldLinkName = myLink.name;

// I assume that all extensions consist of 3 characters

var myExtension = myOldLinkName.substr(-4, 4);

var myNewLinkName = myOldLinkName.split("_", 1).join() + myExtension;

Kasyan

[c.pfaffenbichler]

Thanks, Kasyan.
Unfortunately the naming-discipline is more lax than desirable around here ...

[Kasyan Servetsky]

Im sure this is solvable.
Could you give me examples of all possible suffixes in your workflow?

[c.pfaffenbichler]

Possible suffixes are " end", "_end","_lay", " lay".
It certainly is solvable, but what would be the most economic or elegant way is where Im out of my depth.

[Peter Kahrel]

This deletes any combination of suffixes:

for (i = 0; i < 4; i++)
link_name = link_name.replace (/[ _](end|lay)$/g, "");

Peter

[c.pfaffenbichler]

Thanks, Peter.