Open XML file and list records

[Kleber Silva]

I would like to know if it is possible to use an XML file containing multiple book records so that I could create a window listing all these records for the user to choose. I've tried using the manuals but they seem to me that they are meant for other features, and I'm not sure it's possible to do what I need.

Thanks

[Loic.Aigon · Accepted solution]

Given that you have the following xml structure:

<?xml version="1.0" encoding="UTF-8"?>
 <books>
     <book name="Book 1"/>
     <book name="Book 2"/>
     <book name="Book 3"/>
     <book name="Book 4"/>
 </books>
 

Then you can have

var main = function() {
var m = $.os[0]=="M",
wF = "XML Files : *.xml",
mF = function(f){return (f instanceof Folder ) || /\.xml$/.test(f.name)},
filter = m? mF : wF,
f = File.openDialog ("Please select xml file", filter),
books, nBook, arr = [], n = 0, i = 0;
if ( !f ) return;
f.encoding ="UTF-8";
f.open('r');
x = XML( f.read() );
f.close();
books = x..book;
n = books.length();
if ( !n ) return;
while ( i<n ) {
nBook = books;
arr.push ( String( nBook.@name ) );
i++;
}
openWindow ( arr );
}
var openWindow = function(arr) {
var w = new Window('dialog'),
ls = w.add('listbox', undefined, arr),
btn = w.add('button', undefined, 'Cancel');
w.show();
};
var u;
main()

And see the result