Working with string

[sangn33723990]

Version: Indesign CS 5.5,   ExtendScript Toolkit CS5.5

var aaa=["4+5",6,7];  //my array
alert(aaa[0].length);   //get length of aaa[0]
var x =aaa[0].substring(0,1);   //get  char 
var y =aaa[0].substring(1,1);   
var z =aaa[0].substring(2,1);  
alert(x);
alert(y);
alert(z);

i think result of x ="4",y=", " and z="5" but not right. Mycomputer alert  x="4", z="+".Plese help me explain this.

[rob day]

With the substring method if the argument’s first number is greater than the second they get reversed, so (2,1)  == (1,2)

There is an InDesign scripting forum. You’ll get better answers for coding questions there

[Laubender]

Hi,

you mixed up method substr() with substring().

var s = "4+5";
s.substr(0,1) // 4
s.substr(1,1) // +
s.substr(2,1) // 5

Adobe InDesign CS6 (8.0) Object Model JS: String

Regards,
Uwe

[pixxxelschubser]

Hi sangn33723990​

Better use charAT() in such cases

var x =aaa[0].charAt(0);   //get  char
var y =aaa[0].charAt(1);
var z =aaa[0].charAt(2);

or like Laubender​ mentioned use substr()

or like this

var x =aaa[0].substring(0,1);   //get  char
var y =aaa[0].substring(1,2);
var z =aaa[0].substring(2,3);

^Aktualisiert

explanation

String.substring(indexFirstChar[, indexLastChar]*);  // ]* = optional, if not used --> till the end
String.substr(indexFirstChar[, lenght]*);  // ]* = optional, if not used --> till the end