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Joachim Hiller
Joachim Hiller
Known Participant
March 1, 2019
Answered

get Pattern ID

  • March 1, 2019
  • 3 replies
  • 1982 views

Hi,

is there a way to retrieve the ID of a pattern besides the name?

function getAllPatterns() {
    var ref = new ActionReference();
    ref.putEnumerated(cTID("capp"), cTID("Ordn"), cTID("Trgt"));
    var desc = executeActionGet(ref);
    var List = desc.getList(sTID('presetManager'));
    var patterns = [];
    var list = List.getObjectValue(4).getList(charIDToTypeID('Nm  '));
    for (var i = 0; i < list.count; i++) {
        var str = list.getString(i);
        // $.writeln('str: ' + str);
        patterns.push(str);
    }
    return patterns;
};
getAllPatterns();

Kind Regards

Joe

This topic has been closed for replies.
Correct answer greless

if (app.documents.length > 0) {
var ref = new ActionReference();
 //ref.putProperty(stringIDToTypeID("property"), stringIDToTypeID("layerEffects")); 
ref.putEnumerated( charIDToTypeID("capp"), charIDToTypeID("Ordn"), charIDToTypeID("Trgt") ); 
var layerDesc = executeActionGet(ref);
var layerDesc = layerDesc.getObjectValue(stringIDToTypeID("currentToolOptions"));   
 layerDesc = layerDesc.getObjectValue(stringIDToTypeID("pattern"));        
checkDesc2 (layerDesc);
};
//////
////// based on code by michael l hale //////
function checkDesc2 (theDesc) {
var c = theDesc.count;
var str = '';
for(var i=0;i<c;i++){ //enumerate descriptor's keys
  str = str + 'Key '+i+' = '+typeIDToStringID(theDesc.getKey(i))+'/'+typeIDToCharID(theDesc.getKey(i))+': '+theDesc.getType(theDesc.getKey(i))+':'+getValues (theDesc, i)+'\n';
  };
alert("desc\n\n"+str);
logInfo(str);
};
////// check //////
function getValues (theDesc, theNumber) {
    
        var key = theDesc.getKey(theNumber);  
        var type = theDesc.getType(key);  
            
switch (type) {
case DescValueType.ALIASTYPE:
return theDesc.getPath(key);
break;
case DescValueType.BOOLEANTYPE:
return theDesc.getBoolean(key);
break;
case DescValueType.CLASSTYPE:
return theDesc.getClass(key);
break;
case DescValueType.DOUBLETYPE:
return theDesc.getDouble(key);
break;
case DescValueType.ENUMERATEDTYPE:
return (typeIDToStringID(theDesc.getEnumerationValue(key))+"_"+typeIDToCharID(theDesc.getEnumerationType(key)));
break;
case DescValueType.INTEGERTYPE:
return theDesc.getInteger(key);
break;
case DescValueType.LISTTYPE:
return theDesc.getList(key);
break;
case DescValueType.OBJECTTYPE:
return (theDesc.getObjectValue(key)+"_"+typeIDToStringID(theDesc.getObjectType(key))+"_"+typeIDToCharID(theDesc.getObjectType(key)));
break;
case DescValueType.RAWTYPE:
//return theDesc.getReference(theDesc.getData(theNumber));
break;
case DescValueType.REFERENCETYPE:
return theDesc.getReference(key);
break;
case DescValueType.STRINGTYPE:
return theDesc.getString(key);
break;
case DescValueType.UNITDOUBLE:
return (theDesc.getUnitDoubleValue(key)+"_"+typeIDToStringID(theDesc.getUnitDoubleType(key))+"_"+typeIDToCharID(theDesc.getUnitDoubleType(key)));
break;
default: val =  theDesc.getType(key).toString();
break;
};
};
function logInfo(Txt){  
var file = new File(Folder.desktop + "/style2.txt");  
file.open("w", "TEXT", "????");  
file.seek(0,2);  
$.os.search(/windows/i)  != -1 ? file.lineFeed = 'windows'  : file.lineFeed = 'macintosh';  
file.writeln(Txt);  
file.close();  
};

3 replies

R
r-bin
Legend
March 2, 2019

The pattern can be set in the pattern adjustment layer using only the pattern name, and then you can read the ID from this pattern adjustment layer.

And why do you need it?

Joachim Hiller
Joachim HillerAuthor
Known Participant
March 2, 2019

I first tried the name, but there were problems with the included  patterns.

For the supplied pattern would be another approach necessary as self-created. Thats my Problem

function createPatternFill(name, scale) {

  try {

  //does not work because the name is localized

  // alert(localize("$$$/Presets/Patterns/" + name));


  //included  Pattern
  //German Version
  alert(localize("$$$/Presets/Patterns/" + "Rechts-diagonale Linie 1"));

  var desc1 = new ActionDescriptor();
  var ref = new ActionReference();
  ref.putClass( sTID('contentLayer') );
  desc1.putReference( cTID('null'), ref );
  var desc2 = new ActionDescriptor();
  var desc3 = new ActionDescriptor();
  desc3.putUnitDouble( cTID('Scl '), cTID('#Prc'), scale );
  var desc4 = new ActionDescriptor();

  //included  Patterns
  desc4.putString( cTID('Nm '), localize("$$$/Presets/Patterns/" + name) );

    //for all others
  desc4.putString( cTID('Nm '),  name );


  // desc4.putString( cTID('Idnt'), "bf565312-67b6-1177-9181-9d5762aa7056" );
  desc3.putObject( cTID('Ptrn'), cTID('Ptrn'), desc4 );
  desc2.putObject( cTID('Type'), sTID('patternLayer'), desc3 );
  desc1.putObject( cTID('Usng'), sTID('contentLayer'), desc2 );
  executeAction( cTID('Mk '), desc1, DialogModes.NO );
  }

  catch (e){

  alert(e + "\n" + e.line);
  }

}

greless
grelessCorrect answer
Inspiring
March 2, 2019

if (app.documents.length > 0) {
var ref = new ActionReference();
 //ref.putProperty(stringIDToTypeID("property"), stringIDToTypeID("layerEffects")); 
ref.putEnumerated( charIDToTypeID("capp"), charIDToTypeID("Ordn"), charIDToTypeID("Trgt") ); 
var layerDesc = executeActionGet(ref);
var layerDesc = layerDesc.getObjectValue(stringIDToTypeID("currentToolOptions"));   
 layerDesc = layerDesc.getObjectValue(stringIDToTypeID("pattern"));        
checkDesc2 (layerDesc);
};
//////
////// based on code by michael l hale //////
function checkDesc2 (theDesc) {
var c = theDesc.count;
var str = '';
for(var i=0;i<c;i++){ //enumerate descriptor's keys
  str = str + 'Key '+i+' = '+typeIDToStringID(theDesc.getKey(i))+'/'+typeIDToCharID(theDesc.getKey(i))+': '+theDesc.getType(theDesc.getKey(i))+':'+getValues (theDesc, i)+'\n';
  };
alert("desc\n\n"+str);
logInfo(str);
};
////// check //////
function getValues (theDesc, theNumber) {
    
        var key = theDesc.getKey(theNumber);  
        var type = theDesc.getType(key);  
            
switch (type) {
case DescValueType.ALIASTYPE:
return theDesc.getPath(key);
break;
case DescValueType.BOOLEANTYPE:
return theDesc.getBoolean(key);
break;
case DescValueType.CLASSTYPE:
return theDesc.getClass(key);
break;
case DescValueType.DOUBLETYPE:
return theDesc.getDouble(key);
break;
case DescValueType.ENUMERATEDTYPE:
return (typeIDToStringID(theDesc.getEnumerationValue(key))+"_"+typeIDToCharID(theDesc.getEnumerationType(key)));
break;
case DescValueType.INTEGERTYPE:
return theDesc.getInteger(key);
break;
case DescValueType.LISTTYPE:
return theDesc.getList(key);
break;
case DescValueType.OBJECTTYPE:
return (theDesc.getObjectValue(key)+"_"+typeIDToStringID(theDesc.getObjectType(key))+"_"+typeIDToCharID(theDesc.getObjectType(key)));
break;
case DescValueType.RAWTYPE:
//return theDesc.getReference(theDesc.getData(theNumber));
break;
case DescValueType.REFERENCETYPE:
return theDesc.getReference(key);
break;
case DescValueType.STRINGTYPE:
return theDesc.getString(key);
break;
case DescValueType.UNITDOUBLE:
return (theDesc.getUnitDoubleValue(key)+"_"+typeIDToStringID(theDesc.getUnitDoubleType(key))+"_"+typeIDToCharID(theDesc.getUnitDoubleType(key)));
break;
default: val =  theDesc.getType(key).toString();
break;
};
};
function logInfo(Txt){  
var file = new File(Folder.desktop + "/style2.txt");  
file.open("w", "TEXT", "????");  
file.seek(0,2);  
$.os.search(/windows/i)  != -1 ? file.lineFeed = 'windows'  : file.lineFeed = 'macintosh';  
file.writeln(Txt);  
file.close();  
};
SuperMerlin
SuperMerlin
Inspiring
March 1, 2019

You can get them from the pat files I.E.

var patFolder = Folder("/C/Program Files/Adobe/Adobe Photoshop CS6 (64 Bit)/Presets/Patterns");
var pattern = patFolder.getFiles( "*.pat")[0];
alert(getPatterns(pattern).join("\n"));
function getPatterns(file){
  file.open("r");
  file.encoding = 'BINARY';
  var str = file.read();
  file.close();
  var patterns=[];
  //Thanks to X for the regex
  var re = /(\x00\w|\x00\d)(\x00\-|\x00\w|\x00\s|\x00\d)+\x00\x00\$[-a-z\d]+/g;
  var parts = str.match(re);
  for (var i = 0; i < parts.length; i++) {
    var p = parts;
    var sp = p.replace(/\x00/g, '').split('$');
     patterns.push([[sp[0]], [sp[1]]]);   
     }
 return patterns;
};
    Joachim Hiller
    Joachim HillerAuthor
    Known Participant
    March 1, 2019

    Thanks SuperMerlin​,

    there is no way to get the ID's of all loaded patterns?

    SuperMerlin
    SuperMerlin
    Inspiring
    March 1, 2019

    Not that I know of.

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