how to get brush name?

[greless]

i had been getting the name of  part of the brush.but some of brush name unable to get.the code as fallow:

var param = get_brush_param(); 

// examples 

// show all (almost all) brush props 

alert(obj_to_str(param), "currentTool options"); 

function obj_to_str(obj){var str = ""; for (var p in obj) if(obj.hasOwnProperty(p))try{str+=p+"::"+obj

+"\n";}catch(e){};

      logInfo( str);

    return str;} 

////////////////////////////////////////////////////////////////// 

function get_brush_param() 

    { 

    try { 

        var r = new ActionReference(); 

        r.putProperty(stringIDToTypeID("property"), stringIDToTypeID("tool")); 

        r.putEnumerated(stringIDToTypeID("application"), stringIDToTypeID("ordinal"), stringIDToTypeID("targetEnum")); 

        var d = executeActionGet(r); 

        var options = d.getObjectValue(stringIDToTypeID("currentToolOptions"));   

        var ret = new Object(); 

   //  try { var brush = options.getObjectValue(charIDToTypeID("CrpO")); } catch(e) { alert("Current tool not brush!"); return ret; }  

     try { var brush = options.getObjectValue(stringIDToTypeID("brush")); } catch(e) { alert("Current tool not brush!"); return ret; }  

  // alert( options.count);

  //  alert( brush.count);

        for (var i = 0; i < brush.count; i++) 

            { 

            var key = brush.getKey(i); 

            var type = brush.getType(key); 

            var val = undefined; 

            switch (type)  

                { 

                case DescValueType.BOOLEANTYPE:    val = brush.getBoolean(key); break; 

                case DescValueType.DOUBLETYPE:     val = brush.getDouble(key);  break;   

                case DescValueType.INTEGERTYPE:    val = brush.getInteger(key); break; 

                case DescValueType.ENUMERATEDTYPE: val = typeIDToStringID(brush.getEnumerationValue(key)); break; 

                case DescValueType.UNITDOUBLE:     val = brush.getUnitDoubleValue(key); break; // not quite right 

                  case DescValueType.STRINGTYPE: val = brush.getString(key); break;  

              //  case DescValueType.REFERENCETYPE: val = getReference(brush.getReference(key)); break;  

                default: val =  brush.getType(key).toString();

                } 

            if (val != undefined)  

                { 

                var name = typeIDToStringID(key); 

                if (!name) name = typeIDToCharID(key); 

                if (typeof(val) == "string") 

                    eval("ret." + name +"='"+val+"'");  

                else 

                    eval("ret." + name +"="+val);  

                } 

            }                 

        return ret; 

        } 

    catch (e) { alert(e); } 

    } 

function logInfo(Txt){ 

var file = new File(Folder.desktop + "/too_brush1.txt"); 

file.open("w", "TEXT", "????"); 

file.seek(0,2); 

$.os.search(/windows/i)  != -1 ? file.lineFeed = 'windows'  : file.lineFeed = 'macintosh'; 

file.writeln(Txt); 

file.close(); 

}; 

this is successful.

this is fail,i can't get the name.

[JJMack]

There are different types of Brushes your code seem to handle normal brushed with tound tips.  There are also sample tipped brushes, Mixer Brushes and special bush types.  In other words you code does not have support  for all posible Photosop brush types. There are also Many bursh type tools in Photoshop.

Different brush type have different attributes

[greless]

each preset brushes has a name,so  could we get the name?

[greless]

r-bin​

[r-bin]

It turns out that not all brushes have a property "name".

I do not know how to solve this problem. Maybe later I'll see what can be done.

In this thread Select/refer to brushes by name within brush sets by name

there is an attempt to find out the name of the brush.

See functions alert_curr_brush() and alert_curr_brush_v2().

But for you, most likely, it will not work.

[greless]

Thank you so much in advance and have a nice day.

is this a method that Getting the current preset brushes?

https://forums.adobe.com/message/10046190#10046190

[greless]

the example you offer  try to  running  in CC2017 is fail,but CC2019 is ok,

Is there a way to run CC2017?

[r-bin]

I have not yet found how to find the name of the current brush.
But I found another bug (feature, crap) of Photoshop (CS6 and CC2018 at least)
Rename your brush, which supposedly has the name "Spatter 14 pixels" into another one and try to run the script on the definition of the brush::name property. You will be disappointed

PS. What script are you talking about that works in 2018 and does not work in 2017?