Re: Displaying system time (not timecode)

Dan Ebberts · ‎Apr 25, 2011

Sure: D = new Date(Date(0)); h = D.getHours(); m = D.getMinutes(); s = D.getSeconds(); h = "" + h; if (h.length < 2) h = "0" + h; m = "" + m; if (m.length < 2) m = "0" + m; s = "" + s; if (s.length < 2) s = "0" + s; h + ":" + m + ":" + s Dan

Dan Ebberts · ‎Apr 25, 2011

I haven't tested this thoroughly, but it should get you close: D = new Date(Date(0)); h = D.getHours(); m = D.getMinutes(); suffix = h >= 12 ? "PM" : "AM"; if (h > 12) h -= 12; h = "" + h; if (h.length < 2) h = "0" + h; m = "" + m; if (m.length < 2) m = "0" + m; h + ":" + m +" " + suffix Dan

Dan Ebberts · ‎Apr 08, 2011

I'm afraid you have more work to do. You have to create a file object out of your path, then you have to import the file (see the scripting guide sections on Project importFile() and the ImportOptions object). Once you have imported the file (which will then be a Footage object), you can do the replaceSource(). Dan

Dan Ebberts · ‎Apr 08, 2011

When you do the readch(), at that point you have 8 bits of binary data.You can't display it, because it's binary. All the rest of the code I put in there converts it from binary to the ASCII representation (characters) of the binary so I could display it. Don't do that part if you want keep it as binary. Dan

Dan Ebberts · ‎Apr 08, 2011

This version should generate binary: { var myFile = File.openDialog("Select binary file."); myFile.open("r"); myFile.encoding = "BINARY"; var myChar, myByte; var i = 0; s = ""; while (! myFile.eof){ myChar = myFile.readch(); myByte = myChar.charCodeAt(0).toString(2); while (myByte.length < 8) myByte = "0" + myByte; s += myByte + " "; if (i%8 == 7) s += "\r"; i++; } myFile.close(); $.writeln(s); } I just added the carriage returns to pretty it up for output in the Console window. What are you going to do with the data? Dan

Dan Ebberts · ‎Apr 07, 2011

Are you saying you want the expression to resolve the name of the active item when it runs? That won't work. If what you're trying to do is have the script resolve the name at the time the script runs and build that into the expression, then you'd do it the way I posted previously. Dan

Dan Ebberts · ‎Apr 07, 2011

If you're sure the active item is a comp, it should just be activeItem.name Dan

Dan Ebberts · ‎Apr 07, 2011

If you have access to the comp object, you should be able to just drop its name into the expression string, like this: var myExpr = 'comp("' + myComp.name + '").layer("layer name")......etc. Or am I missing something? Dan

Dan Ebberts · ‎Apr 07, 2011

Actually, I got the same results on both. Dan

Dan Ebberts · ‎Apr 07, 2011

If I do it this way: { var myFile = File.openDialog("Select binary file."); myFile.open("r"); myFile.encoding = "BINARY"; var myChar, myByte; var i = 0; s = ""; while (! myFile.eof){ myChar = myFile.readch(); myByte = myChar.charCodeAt(0).toString(16); if (myByte.length < 2) myByte = "0" + myByte; s += myByte + " "; if (i%16 == 15) s += "\r"; i++; } myFile.close(); $.writeln(s); } This is what I get: 4d 4d 00 2a 00 00 00 08 00 0c 00 fe 00 04 00 00 00 01 00 00 00 00 01 00 00 03 00 00 00 01 00 04 00 00 01 01 00 03 00 00 00 01 00 04 00 00 01 02 00 03 00 00 00 03 00 00 00 9e 01 03 00 03 00 00 00 01 00 01 00 00 01 06 00 03 00 00 00 01 00 02 00 00 01 11 00 04 00 00 00 01 00 00 00 bc 01 15 00 03 00 00 00 01 00 03 00 00 01 16 00 03 00 00 00 01 00 04 00 00 01 17 00 04 00 00 00 01 00 00 00 30 01 1c 00 03 00 00 00 01 00 01 00 00 86 49 00 01 00 00 00 18 00 00 00 a4 00 00 00 00 00 08 00 08 00 08 38 42 49 4d 04 28 00 00 00 00 00 0c 00 00 00 01 3f f0 00 00 00 00 00 00 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff Dan

Dan Ebberts · ‎Apr 07, 2011

I can't think of a good way to model that with a formula. If it was me, I think I'd keyframe it once on a template null and then link to that motion using valueAtTime() from the Bezier expessions. The exact expression would depend on what you're using to trigger the animation. Dan

Dan Ebberts · ‎Apr 07, 2011

When I run this, I get 236 which indicates to me that myBuffer has all the data from the image: { var myFile = File.openDialog("Select binary file."); myFile.open("r"); myFile.encoding = "BINARY"; var myBuffer = myFile.read(); myFile.close(); alert(myBuffer.length); } Dan

Dan Ebberts · ‎Apr 06, 2011

OK - I can see how it looks now, but it would be helpful if you could keframe an example of how you want it to look. Dan

Dan Ebberts · ‎Apr 05, 2011

I'm not sure what you're describing exactly. The expression you're using generates a damped sine wave. What would the new waveform look like? Would it be the same except eased so the the wave spends more time close to the extremes and less time transitioning, or something else entirely? You could build your own, triple-eased periodic waveform like this, but I'm not sure it's what you're after: veloc = 14; amplitude = -250; decay = 4; period = (Math.PI*2)/veloc; t = (time+period/4)%period; if (t < period/2) v = ease(t,0,period/2,-1,1) else v = ease(t,period/2,period,1,-1); v = ease(v,-1,1,-1,1); v = ease(v,-1,1,-1,1); amplitude*v/Math.exp(decay*time) Dan

Dan Ebberts · ‎Mar 30, 2011

Expressions can only affect the value of property to which they are applied. They can however, access (read-only) most parameters and attributes of any other composition and its layers. So you could have a slider control, for example, in one comp that could be read by expressions in any other comp. That slider control could have an expression controlling its value, but no other expression could affect the value. Does that answer your question? If not, please be more specific about what it is you're trying to do. Dan

Dan Ebberts · ‎Mar 28, 2011

Hmmm.... All I have to do is change the bar animation to start at the first keyframe and end at the second, and it works perfectly for me. In any case, I'm glad you got it working. Dan

Dan Ebberts · ‎Mar 28, 2011

I think the problem is that your keyframes don't line up with the start and stop of the bar animation. The expression can only tell where the keyframes are, it doesn't know that the first keyframe actually occurs 17 frames before the layer becomes visible and the 2nd keyframe occurs some time after the bar is fully extended. So I think the expression is doing what it should, relative to the animation of the mask -- it's just that it doesn't correspond to the timing you're expecting as fas a the anmiation of the bar itself. Dan

Dan Ebberts · ‎Mar 28, 2011

The expression is set up to have the slider control the duration of the animation. If you want it to control the end time, this should work: dur = thisComp.layer("control").effect("duration")("Slider"); t = time; if (numKeys > 1){ t1 = key(1).time; t2 = key(2).time; if (time > t1){ t = ease(time,t1,dur,t1,t2); } } valueAtTime(t) Dan

Dan Ebberts · ‎Mar 28, 2011

If the animation has exactly two keyframes, and you have layer named "control" with a slider named "duration", this should work: dur = thisComp.layer("control").effect("duration")("Slider"); t = time; if (numKeys >1){ t1 = key(1).time; t2 = key(2).time; if (time > t1){ t = ease(time,t1,t1+dur,t1,t2); } } valueAtTime(t) Dan

Dan Ebberts · ‎Mar 26, 2011

Try this: threshold = 10.0; audioLev = thisComp.layer("Audio Amplitude").effect("Both Channels")("Slider"); above = false; frame = timeToFrames(); n = 0; while (frame >= timeToFrames(inPoint)){ t = frame * thisComp.frameDuration; if (above){ if (audioLev.valueAtTime(t) < threshold){ above = false; } }else if (audioLev.valueAtTime(t) >= threshold){ above = true; n++; } frame-- } n Dan

Dan Ebberts · ‎Mar 26, 2011

Yeah, sure -- I'd like to see the project. Dan

Dan Ebberts · ‎Mar 26, 2011

Rick, I think this should do it: threshold = 10.0; audioLayer = thisComp.layer("Audio Amplitude") audioLev = audioLayer.effect("Both Channels")("Slider"); above = false; frame = Math.round(time / thisComp.frameDuration); n = 0; while (frame >= timeToFrames(audioLayer.inPoint)){ t = frame * thisComp.frameDuration; if (above){ if (audioLev.valueAtTime(t) < threshold){ above = false; } }else if (audioLev.valueAtTime(t) >= threshold){ above = true; n++; } frame-- } n Dan

Dan Ebberts · ‎Mar 26, 2011

That expression would be applied to the camera's Focus Distance property. Dan

Dan Ebberts · ‎Mar 18, 2011

Replacing text shouldn't affect the paragraph justification. I've never heard of the replaceTextInLayer() function. Is it possible that you inherited a script from someone and that function is defined somewhere in the code (or maybe in an include file)? In any case, control of justification came in with CS4 and you can see the details here: http://blogs.adobe.com/toddkopriva/2008/12/after-effects-cs4-scripting-ch.html Dan

Dan Ebberts · ‎Mar 17, 2011

This should work better, but I don't think that it will solve your persistance problem. s = "" + (100 - Math.round(time%1*100)); s = s.length < 2 ? "0"+s : s; s.substr(-2) Dan

Dan Ebberts · ‎Mar 17, 2011

This shold mirror a layer across the center of the comp from a null or light named "flare": mult = -1; flare = thisComp.layer("flare"); compCenter = [thisComp.width,thisComp.height]/2; compCenter + mult*(flare.toComp([0,0,0]) - compCenter); Adjust the value of mult to adjust the distance. Dan

Dan Ebberts · ‎Feb 15, 2011

You may have deduced this, but just to clarify -- the only way to control a property with an expression is by applying an expression to that property. Expressions can't affect anything except the property to which they're applied. Dan

Dan Ebberts · ‎Feb 15, 2011

You are correct on all counts. If you have a ton of these to do, you could write a little script that would go through the comp, looking for layers with Colorama applied, and change the Mask layer parameter, but that might be more trouble than it's worth. Dan

Dan Ebberts · ‎Feb 15, 2011

If I understand what you're trying to do, I don't think you can do it with expressions. Colorama's layer control won't accept its own expression (it's not keyframable) and you can't control any property using an expression applied to a different property. Think of expressions as a substitue for keyframes -- if you can't keyframe it, you can't control it with an expression. Dan

Dan Ebberts · ‎Feb 09, 2011

The expressin always controls the value, but just like between odd and even keyframes, you can define regions where the expression's result is "value" which tells the expression to just use the property's pre-expression (keyframed) value. It's hard to give a general answer though, because the solution always depends on exactly what it is you're trying to do. Dan

Dan Ebberts

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