Re: Multiple Expressions

Dan Ebberts · ‎Feb 09, 2011

Something like this should work: freq = 1; amp = 25; n = 0; if (thisProperty.numKeys > 0){ n = thisProperty.nearestKey(time).index; if (thisProperty.key(n).time > time) n--; } if (n > 0 && n < thisProperty.numKeys && n%2 == 0){ t1 = thisProperty.key(n).time; t2 = thisProperty.key(n+1).time; if (time > (t1 + t2)/2) easeOut(time,t1,t2,wiggle(freq,amp),value) else easeIn(time,t1,t2,value,wiggle(freq,amp)); }else value Dan

Dan Ebberts · ‎Feb 09, 2011

Yes. The way you would do it depends on what you're trying to accomplish though. Dan

Dan Ebberts · ‎Feb 09, 2011

It's possible to set an expression up so that it is triggered by markers or runs at specific times, but the specifics depend on what it is you're trying to do. Dan

Dan Ebberts · ‎Feb 09, 2011

Play around with this: seedRandom(index,true); offset = random([-1000,-1000,-1000],[1000,1000,1000]); wiggle(1,100) + offset Dan

Dan Ebberts · ‎Feb 09, 2011

The comp and layer names need to be in quotes. Dan

Dan Ebberts · ‎Feb 09, 2011

Assuming that you're talking about horizontal movement and the width of your wheel layer is the same as the wheel's diameter, the relationship will be like this: x = comp("Main Comp").layer("Car").transform.position[0]; 360*x/(Math.PI*width) If you want to tie the rotation to how far the car has moved, you might do it like this: P = comp("Main Comp").layer("Car").transform.position; x = P[0] - P.valueAtTime(0)[0]; 360*x/(Math.PI*width) Dan

Dan Ebberts · ‎Jan 18, 2011

Exactly. Extendscript doesn't have the web/html objects, just the core components of the JavaScript language. Dan

Dan Ebberts · ‎Jan 18, 2011

Going back to your original example, if you change document.write to alert it will execute. You apparently can use the toolkit to write and debug vanilla ExtendScript without specifying a target application. You just won't have access to any of the application-specific extensions. Dan

Dan Ebberts · ‎Jan 13, 2011

Unfortunately, all that expressions layer space transform goodness doesn't exist in the scripting world. The easiest way to do it might be to have the scipt apply a slider to which it then applies the appropriate expression, for each dimension and each corner and harvest the result each time. So you'd apply the slider, apply the 12 expressions (reading the value each time) and delete the slider. If everything is 2D, you could use a point control and only have to apply 4 expressions (one for each corner). Dan

Dan Ebberts · ‎Jan 08, 2011

There is more than one possible answer to your question, depending on what you're doing. For example, if your 3D layer always faces the camera, a scale expression like this should work: L = thisComp.layer("my3DLayer"); p1 = L.toComp([0,0,0]); p2 = L.toComp([L.width,0,0]); d = length(p1,p2); value*d/L.width Dan

Dan Ebberts · ‎Dec 08, 2010

Assuming you're on a Windows machine, var myFile = File($.fileName); alert(myFile.fsName); Dan

Dan Ebberts · ‎Dec 08, 2010

Try this: unescape($.fileName) Dan

Dan Ebberts · ‎Dec 03, 2010

Pretty much. toComp() is what you use to get the 2D position in the comp view. Dan

Dan Ebberts · ‎Dec 02, 2010

Hard to say without looking at it. What's the exact expression you're using? Also, are all layers and comps square pixels? Dan

Dan Ebberts · ‎Dec 02, 2010

Try changing the last line to this: L2.toComp(P1) Dan

Dan Ebberts · ‎Dec 01, 2010

The precomp is the source for the layer. Try this: var myComp = app.project.activeItem; var myLayer = myComp.selectedLayers[0]; alert (myLayer.source.numLayers); Dan

Dan Ebberts · ‎Nov 30, 2010

Try this for the platform-specific path: app.project.file.fsName or this for the URI path, app.project.file.fullName Dan

Dan Ebberts · ‎Nov 22, 2010

To change the position, you need to use setValue(), like this: var newWidth = app.project.activeItem.width; var newHeight = app.project.activeItem.height; for(var i = 1; i<= activeComp.numLayers;i++){ activeComp.layer(i).position.setValue([newWidth / 2, newHeight / 2]); } Dan

Dan Ebberts · ‎Nov 19, 2010

Like this: thisComp.numLayers Dan

Dan Ebberts · ‎Nov 04, 2010

It's pretty straight forward, but it's not trivial. There may be something out there already that does this, but I'm not sure where. Basically, you need something that will drill down, recursively through all the properties in a layer, see if the property can accept an experssion, see if it has an expression, and then do a text replace on "thisComp". (It doesn't seem like you'd need to worry about "thisLayer"). There are examples out there on how to do the recursive part (which is where most of the work is). Dan

Dan Ebberts · ‎Oct 29, 2010

That should work if they're both nulls, but this is probably the better way to do it: thisComp.layer("childNULL").toWorld([0,0,0]) Or maybe this, if it's all 2D stuff: thisComp.layer("childNULL").toComp([0,0,0]) Dan

Dan Ebberts · ‎Oct 17, 2010

With an expression? You can use [width,height]/2 but it will cause the layer to jump to a new position. Dan

Dan Ebberts · ‎Oct 17, 2010

Sure. In that case you would attach each effect point like this: fromComp(thisComp.layer("Null 1").toComp([0,0,0])) Dan

Dan Ebberts · ‎Oct 17, 2010

This is the key: myRQItem.outputModules.add(); myOM = myRQItem.outputModule(2); myOM.applyTemplate(myOutputModule2); Dan

Dan Ebberts · ‎Oct 16, 2010

Say you have two lens flares applied to the same layer. Assuming you want to control the angle of the second flare relative to the first flare with an Angle Control, you could use an expression like this for the second flare's center point: angle = effect("Angle Control")("Angle"); p1 = toComp(effect("Lens Flare")("Flare Center")); p2 = toComp(value); delta = p2 - p1; radius = length(p2,p1); a = Math.atan2(delta[1],delta[0]); newAngle = a + degreesToRadians(angle); x = radius*Math.cos(newAngle); y = radius*Math.sin(newAngle); p1 + fromComp() Dan

Dan Ebberts · ‎Oct 06, 2010

This should do it: offset = 25; // positive makes line longer n = thisComp.numLayers; v1 = thisComp.layer(n-1).position; v2 = thisComp.layer(n).position; v = normalize(v2 - v1)*offset; v2 += v; v1 -= v; if (index == 1){ v1 }else if (index == n-2){ v2 }else{ v1 + (v2 - v1)*((index-1)/(n-3)) } Dan

Dan Ebberts · ‎Oct 06, 2010

Vectors don't really have a position, just length and direction. What are you trying to do exactly? Dan

Dan Ebberts · ‎Sep 25, 2010

Like this: if (comp("Main Comp").layer(thisComp.name).toCompVec([0, 0, 1])[2] > 0 ) value else 0 Dan

Dan Ebberts · ‎Sep 23, 2010

Set the Falloff parameter for that output to "None(Integrate)". Dan

Dan Ebberts · ‎Sep 10, 2010

Are you talking about changing the list, or other controls? If it's the list and something has changed, I would usually use removeAll() to remove all the items from the list and then just call the routine that populated the list to begin with. Pretty much everything you need for script interface development is in Adobe's JavaScript Tools Guide. Dan

Dan Ebberts

Dan Ebberts

Activity

Re: Multiple Expressions

Re: Multiple Expressions

Re: Multiple Expressions

Re: Random vs. Noise

Re: linking precomped wheel rotation to position i...

Re: linking precomped wheel rotation to position i...

Re: How to use Javascript Tools? does it has one f...

Re: How to use Javascript Tools? does it has one f...

Re: coordinates of layer corners

Re: Layer Space Transforms and Size

Re: How do I determine the path and name of the sc...

Re: How do I determine the path and name of the sc...

Re: How to get relative position of layer in large...

Re: How to get relative position of layer in large...

Re: How to get relative position of layer in large...

Re: Count layers within precomposed layer

Re: How determine the absolute path of the aep-pro...

Re: Resize Composition to Layers Scale

Re: Layers in a comp

Re: Changing Expressions reference from relative t...

Re: Getting global coordinates from parented local...

Re: Center Anchor Point at a Layer

Re: How to rotate a point around another one

Re: Adding extra output modules in AE script

Re: How to rotate a point around another one

Re: lengthen or shorten vector

Re: lengthen or shorten vector

Re: Layer1 invisible when Layer2 facing away from ...

Re: An expression to Count up, to use in conjuncti...

Re: Interface