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A
Anonymous
February 6, 2019
Question

Set page Label without numbering style

  • February 6, 2019
  • 3 replies
  • 963 views

Is it possible to apply a page label without numbering style like we can using style "none" with page numbering in Acrobat?

var labels = "4, 9, 13";

var labelsplit = labels.split(", ");

if (labelsplit.length == this.numPages) {

    for (var i=0; i<this.numPages; i++) {

            this.setPageLabels(i, ["D", "", labelsplit]);

            //this.setPageLabels(i, ["r", "", labelsplit]);

            //this.setPageLabels(i, [ "A", "C4-Lot", 4])

    }

}

My problem is if my labels contain something else than integer...

For a label like "C4-LotD" I would have to evaluate if the last letter is upper case and then "D" is the fourth letter of alphabetical order to come out with:

this.setPageLabels(i, [ "A", "C4-Lot", 4])

Label not ending by alphanumeric character will be a problem. Maybe another way to label pages?

This topic has been closed for replies.

3 replies

BarlaeDC
BarlaeDC
Community Expert
February 7, 2019

Hi,

Are the page label endings predictable, i.e. they are a known set of characters that are allowed or are all characters allowed?

Regards

Malcolm

    A
    Anonymous
    February 12, 2019

    After research chance are that labels will end by alphanumerical characters. The only way I found to get a label otherwise is to use Acrobat and put numbering style to "none". This way suggest to label each page one by one which should be rare.

    For now i will deal with non-alphanumerical character by adding a "1" and the end. So I will use:

    var labels = "I,II,1,2,A,B,@_!";

    labelsplit = labels.split(",");

    var pageLabel = "";

    var prefix = "";

    var nStart = 1

    if (labelsplit.length == this.numPages) {

        for (var i=0; i<this.numPages; i++) {

                pageLabel = labelsplit;

                mDecimal = pageLabel.match(/\d+$/);

            if (mDecimal) {

                nStart = mDecimal[0];

                prefix = pageLabel.slice(0, mDecimal[0].length*-1);

                this.setPageLabels(i, ["D", prefix, nStart]);

            }

            else{

                prefix = pageLabel.slice(0, -1);

                charAsNumber = pageLabel.charCodeAt((pageLabel.length - 1));

                if (charAsNumber > 64 && charAsNumber < 91) {

                     //is uppercase letter

                    this.setPageLabels(i, [ "A", prefix, charAsNumber -= 64])

                }

                else if (charAsNumber > 96 && charAsNumber < 123) {

                //is lowercase letter

                    this.setPageLabels(i, [ "a", prefix, charAsNumber -= 96])

                }

                else{

                    //dealing with non-alphanumeric ending, for now add at numbering "1"

                    this.setPageLabels(i, [ "D", pageLabel, 1])

                }

            }

        }

    }

    Is there a way to label a page without numbering style?

    A
    Anonymous
    February 7, 2019

    Thanks, I did'nt know that method. My idea for resolving the char number was to create an array A-Z then do a find to retreive the index number. Still don't know how resolving Label not ending by alphanumeric character...

    BarlaeDC
    BarlaeDC
    Community Expert
    February 6, 2019

    Hi,

    I don't know if pages labels can be created as you want but working out which number a letter is, is pretty trivial, you could just use.

    var pageLabel = "C4-LotD";

    // make string uppercase, get last char

    var charAsNumber = pageLabel.toUpperCase().charCodeAt((pageLabel.length - 1));

    // subtract 64 as that is the start ( well 1 less than an A in ASCII )

    charAsNumber -= 64;

    this would set the string as a number, no matter if it was uppercase or lowercase, you would get the same number ( I am making the assumption that is what you want)

    Caveat: wont work with extended chars.

    Regards

    Malcolm

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