Call an ExtendScript Script from the Command Line

Try this code:

var path = app.scriptArgs.getValue( "indd_path" );

cmd:

sampleclient -host localhost:185 C:\Script\main.jsx indd_path="a.indd"

Hi Rick

I answered the question over here Re: Create a build script for Extend Script

I have some more info on it if needed but don't have time to post it this week.

Regards

Trevor

page 11 in the user manual

Automatic jsxbin Conversion

The jsxbin format (Binary JavaScript) enables distributing a script without exposing its source code. The

ExtendScript ToolKit offers an Export to Binary feature that instantly converts a js(x) file into jsxbin. The

jsxbin export process can be done automatically without user interaction.

To do this:

1. Write a compiler script file that compiles .jsx files into a .jsxbin file.

 The script file must start with this target directive:

#target estoolkit#dbg

 Use the app.compile() method and pass the content of the script file as a String parameter.

 In the script, store the result in a new file with the extension .jsxbin.

2. Launch the ExtendScript ToolKit with the command-line parameter -cmd [path to compiler script file]:

Windows:

"ExtendScript Toolkit.exe" -cmd compiler.jsx

Mac:

"ExtendScript Toolkit.app/Contents/MacOS/ExtendScript Toolkit" \

-cmd compiler.jsx

Here is a sample compiler script (compiler.jsx) with the source script's file path hardcoded.

#target estoolkit#dbg

var fileIn = File("/c/jsxbin_test/source.jsx");

fileIn.open("r");

var s = fileIn.read();

fileIn.close();

var t = app.compile(s);

var fileOut = File( fileIn.absoluteURI + "bin" ) ;

fileOut.open("w");

fileOut.write(t);