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A
Anonymous
September 11, 2017
Answered

Combine Swatches with same value, different name

  • September 11, 2017
  • 2 replies
  • 4805 views

I come across indds that predominantly contain swatches that are named differently but are the same exact color, value-wise, i.e. their C=n, M=n, Y=n, K=n, are the exact same.

I’m looking for a script that will recognize swatches with identical values, i.e. identical CMYK values, and do away with duplicate swatches that share the same values and leave only one swatch, with the name as “Name with Color Value (screenshot below).”

So in the end, there is only one instance of a specific color, and it’s name as CMYK, etc.

Any help, as always, is very much appreciated.

Thanks.

Name with Color Value.

This topic has been closed for replies.
Correct answer Marc Autret

This may work:

function normalizeCMYK(/*Document*/doc,  swa,a,r,o,t,k,i)
// -------------------------------------
// Remove CMYK swatch duplicates and set every name in `C= M= Y= K=` form.
{
    if( !doc ) return;
    const __ = $.global.localize;
    const CM_PROCESS = +ColorModel.PROCESS;
    const CS_CMYK    = +ColorSpace.CMYK;
    swa = doc.swatches;
    a = doc.colors.everyItem().properties;
    r = {};
    // Gather CMYK swatches => { CMYK_Key => {id, name}[] }
    // ---
    while( o=a.shift() )
    {
        if( o.model != CM_PROCESS ) continue;
        if( o.space != CS_CMYK ) continue;
        t = swa.itemByName(o.name);
        if( !t.isValid ) continue;
        for( i=(k=o.colorValue).length ; i-- ; k=Math.round(k) );
        k = __("C=%1 M=%2 Y=%3 K=%4",k[0],k[1],k[2],k[3]);
        (r||(r=[])).push({ id:t.id, name:t.name });
    }
    // Remove dups and normalize names.
    // ---
    for( k in r )
    {
        if( !r.hasOwnProperty(k) ) continue;
        t = swa.itemByID((o=(a=r)[0]).id);
        for( i=a.length ; --i ; swa.itemByID(a.id).remove(t) );
        
        if( k == o.name ) continue; // No need to rename.
        try{ t.name=k }catch(_){}   // Prevent read-only errors.
    }
};
normalizeCMYK(app.properties.activeDocument);

@+

Marc

2 replies

L
Community Expert
LaubenderCommunity Expert
Community Expert
January 20, 2022

Hi ohbfcu,

could be that this code was damaged by moving the thread from the old InDesign Scripting forum to this one a couple of years ago.

 

Look for the original code at Marc Autret's website:

 

3/ Graphics and Geometry
How to Normalize CMYK Swatches
Marc Autret, June 11, 2018

https://www.indiscripts.com/post/2018/06/indesign-scripting-forum-roundup-12#hd3sb1

 

Regards,
Uwe Laubender

( ACP )

    Marc Autret
    Marc AutretCorrect answer
    Legend
    September 13, 2017

    This may work:

    function normalizeCMYK(/*Document*/doc,  swa,a,r,o,t,k,i)
    // -------------------------------------
    // Remove CMYK swatch duplicates and set every name in `C= M= Y= K=` form.
    {
        if( !doc ) return;
        const __ = $.global.localize;
        const CM_PROCESS = +ColorModel.PROCESS;
        const CS_CMYK    = +ColorSpace.CMYK;
        swa = doc.swatches;
        a = doc.colors.everyItem().properties;
        r = {};
        // Gather CMYK swatches => { CMYK_Key => {id, name}[] }
        // ---
        while( o=a.shift() )
        {
            if( o.model != CM_PROCESS ) continue;
            if( o.space != CS_CMYK ) continue;
            t = swa.itemByName(o.name);
            if( !t.isValid ) continue;
            for( i=(k=o.colorValue).length ; i-- ; k=Math.round(k) );
            k = __("C=%1 M=%2 Y=%3 K=%4",k[0],k[1],k[2],k[3]);
            (r||(r=[])).push({ id:t.id, name:t.name });
        }
        // Remove dups and normalize names.
        // ---
        for( k in r )
        {
            if( !r.hasOwnProperty(k) ) continue;
            t = swa.itemByID((o=(a=r)[0]).id);
            for( i=a.length ; --i ; swa.itemByID(a.id).remove(t) );
            
            if( k == o.name ) continue; // No need to rename.
            try{ t.name=k }catch(_){}   // Prevent read-only errors.
        }
    };
    normalizeCMYK(app.properties.activeDocument);

    @+

    Marc

      L
      Community Expert
      LaubenderCommunity Expert
      Community Expert
      September 19, 2017

      Hi Marc,

      just tested your code.

      Two remarks:

      1. Swatches that defined as
      Cyan, Magenta and Yellow = 0 and Black = 100

      are converted to [Black].


      That can be ok. Or not. Perhaps one wanted to make a distinction between a [Black] that is always overprinting—depending on set preferences—and a Black that is not overprinting automatically.

      2. Swatches defined as

      Cyan, Magenta, Yellow and Black = 0

      will throw an error in line 36 of your posted code:

      "Diese Farbe kann nicht gelöscht werden."

      $ID/CantDeleteColorError

      Error number 90898

      Regards,
      Uwe

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