Get values for Measure Tool

My hope is to get results similar to using the measure tool in Photoshop to get an arbitrary rotation.

I have looked around and I have been unable to find a possible way to access the info for Measure Tool. So I tried this.

var myInfoDialog = app.dialogs.add({name:"Alignment", canCancel:true});
    with(myInfoDialog){
    //Add a dialog column.
    with(dialogColumns.add()){
        //Create a border panel.
        with(borderPanels.add()){
            with(dialogColumns.add()){
                //The following line shows how to set a property as you create an object.
                staticTexts.add({staticLabel:"Please Choose Verticalor Horizontal  Alignment     "});
            }
        with(dialogColumns.add()){
        //Create a border panel.
        with(borderPanels.add()){
        var myOrient = radiobuttonGroups.add();    
    with(myOrient){
        radiobuttonControls.add({staticLabel:"Vertical", checkedState: true});
    radiobuttonControls.add({staticLabel:"Horizontal", checkedState: false});
    }
}
            }
        }
    }
}
var myResult = myInfoDialog.show();
if(myResult == true){
    if(myOrient.selectedButton ==1){
        var myAlignment=0;
        }
    else{
        var myAlignment=90;
        }
findAngle();
}
function findAngle(){
    myPath=app.selection[0];
   var lineStart = myPath.paths.item(0).pathPoints.item(0).anchor;
   var lineEnd = myPath.paths.item(0).pathPoints.item(-1).anchor;
   var a = Math.abs(lineStart[0]-lineEnd[0]);
   var o = Math.abs(lineStart[1]-lineEnd[1]);
    c = (180/Math.PI) * Math.atan2(o,a);
    c=c-myAlignment
   if(lineStart[0] < lineEnd[1]){
      c = -c;
   };
   var myRotateMatrix = app.transformationMatrices.add({counterclockwiseRotationAngle:c});
   myPath.transform(CoordinateSpaces.pasteboardCoordinates, AnchorPoint.CENTER_ANCHOR, myRotateMatrix);
   dSelect=app.selection=NothingEnum.NOTHING;
  
};

Unfortunatley it only works on the first rotation. For some reason on subsiquint rotations it fails to return to a 90 degree angle.

Any help with this would be great.