How can I find the leftmost image in sel[j].geometricBounds?

Question

When selecting multiple images, the leftmost image may not necessarily be the first in the array.It could be the topmost image.I guess that sel[j].geometricBounds[1] has the smallest value, which is the leftmost image visually. I want to use it as a reference and get its geometricBounds[1] value.I now need to find the leftmost image among three images. How should I write the code? Thnaks. var sel = app.documents[0].selection;
for(i=0;i<sel.length;i++){ .

. . . . .
var leftmost = (sel[i].geometricBounds)[1];
}

rob day · Accepted Answer

You can check the left bounds against the left bounds of first object in the selection like this

var sel = app.documents[0].selection;

//get the left bounds of the first object in the selection
var lm = sel[0].geometricBounds[1]

//check the left bounds of the other objects
for (var i = 1; i < sel.length; i++){
    if (sel[i].geometricBounds[1] < lm) {
        lm = sel[i].geometricBounds[1]
    } 
};   
alert("Left side of the selection: " + lm)

Sign up

To post, reply, or follow discussions, please sign in with your Adobe ID.

Sign in to Adobe Community

To post, reply, or follow discussions, please sign in with your Adobe ID.

Scanning file for viruses.

This file cannot be downloaded