How can this script read paragraph styles within the group?

Question

Currently, it can only read the external B1.A1 and A2 are not recognized.makeDialog();
//cs will hold the result
var cs, ps;
function makeDialog() {
    //the dialog object
    var theDialog = app.dialogs.add({ name: "Test ", canCancel: true });
    //add a dropdown list object, stringList gets the name of every available character style
    //note this would not get grouped styles
    with (theDialog.dialogColumns.add()) {

staticTexts.add({ staticLabel: "UP：  " });
        staticTexts.add({ staticLabel: "Below：  " });
        staticTexts.add({ staticLabel: "Change：  " });

}
    //note this would not get grouped styles
    with (theDialog.dialogColumns.add()) {
        styleA = dropdowns.add({ stringList: app.activeDocument.paragraphStyles.everyItem().name, selectedIndex: 0, minWidth: 80 });
        styleB = dropdowns.add({ stringList: app.activeDocument.paragraphStyles.everyItem().name, selectedIndex: 0, minWidth: 80 });
        styleBN = dropdowns.add({ stringList: app.activeDocument.paragraphStyles.everyItem().name, selectedIndex: 0, minWidth: 80 });
    }

if (theDialog.show() == true) {
        //get the result
        //cs = app.activeDocument.characterStyles.item(cs.selectedIndex);
        styleA = app.activeDocument.paragraphStyles.item(styleA.selectedIndex);
        styleB = app.activeDocument.paragraphStyles.item(styleB.selectedIndex);
        styleBN = app.activeDocument.paragraphStyles.item(styleBN.selectedIndex);
        theDialog.destroy();
    }
}668.png

m1b · Accepted Answer

The important difference is using the "paragraphStyles" property vs the "allParagraphStyles" property. The latter gives an Array of every paragraph style in the document. The former only returns the paragraphs styles on that level (eg. root level of the document or, if you are looking at a ParagraphStyleGroup, then the styles in that group).

So you can do this:

var doc = app.activeDocument;
var paragraphStyleNames = [];
for (var i = 0; i < doc.allParagraphStyles.length; i++)
    paragraphStyleNames.push(doc.allParagraphStyles[i].name);

and use that list to populate your menu.

- Mark

P.S. I tried to use your actual code but it didn't work for me.

rob day · Answer

Hi @dublove , Are you building or controling the styles via the script? If not there can be any number of nested styles and groups with the same name. What would you do with a case like this?:

Screen Shot 5.png

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