How to obtain the longest character with "：" and the offset value of the first character after "："?

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I have chosen some regular text, and I want to get the horizontalOffset of the first character after the longest character '：'.

The horizontal offset of the word I circled in the picture.
May I ask how to write the code?

Thank you very much.

horizontalOffset.indd

Peter KahrelCorrect answer

Community Expert

Select the text frame with the colons (or select a few lines), then…

app.findGrepPreferences = null;
app.findGrepPreferences.findWhat = ': \\K';
x = app.selection[0].findGrep();

max = 0;
for (i = 0; i < x.length; i++) {
  max = Math.max (x[i].horizontalOffset);
}

alert (max);

Peter Kahrel

Correct answer

Community Expert

Select the text frame with the colons (or select a few lines), then…

app.findGrepPreferences = null;
app.findGrepPreferences.findWhat = ': \\K';
x = app.selection[0].findGrep();

max = 0;
for (i = 0; i < x.length; i++) {
  max = Math.max (x[i].horizontalOffset);
}

alert (max);

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dubloveAuthor

Legend

Hi @Peter Kahrel

I tested it
alert(x[i].horizontalOffset);
It seems that none of the three values are correct.

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Peter Kahrel

Community Expert

Well, you wanted the biggest value, so there's only one correct value.

In what way is it not correct?

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