ImageCatalog Script: Help with layout

Hi @Rocio_Davidge , Not sure if this helps, but you could get the label frame bounds from the image bounds. This creates a label using Mark’s grep and the image frame bounds for a direct selected image:

//set the scripting units
app.scriptPreferences.measurementUnit = MeasurementUnits.POINTS;
var removeThese = /[\._](ai|tif|pdf|psd|jpg|eps|Back|Front|back|front|Halfscale|halfscale|10thscale|tenthscale|Tenthscale|quarterscale|Quarterscale|Gang|gang)/g;

//the label height
var lh = 32;
var doc = app.activeDocument
var lLayer = doc.layers.item(1)

//a selected image
var myImage = doc.selection[0];
if (sel.constructor.name == "Image") {
    //get the image name and strip ext.
    var lc = myImage.itemLink.name.replace(removeThese, '')
    //get the container frame’s bounds
    var b = myImage.parent.geometricBounds;
    //the parent page
    var pp = myImage.parentPage;
    //the label frame placed underneath the image frame
    var myTextFrame = pp.textFrames.add ({ geometricBounds: [b[2], b[1], b[2]+lh, b[3]], itemLayer:lLayer, fillColor:"None", contents:lc});
}

app.scriptPreferences.measurementUnit = AutoEnum.AUTO_VALUE;

Edit: just noticed @Loic.Aigon suggested the same thing. Well, here's an example of what Loic meant...

Hi @Rocio_Davidge, this is not answering your question, but just might be helpful ... you can condense all your string replacements into one RegExp. Like this, for example:

var removeThese = /[\._](ai|tif|pdf|psd|jpg|eps|Back|Front|back|front|Halfscale|halfscale|10thscale|tenthscale|Tenthscale|quarterscale|Quarterscale|Gang|gang)/g;

var myTextFrame = myFrame.parent.textFrames.add(myDocument.layers.item(1), undefined, undefined, { geometricBounds: [300, 637, 53.5, 682], contents: myLabel.replace(removeThese, '') });

It first matches either . or _ followed by any of the words delimited by the bar ( | ). "g" at the end means it keeps matching after the first match, and you can add "i" after "g" to make the matching case insensitive (in which case you can remove Back or back, etc.).

- Mark