Skip to main content
H
hobbes_1979
Participant
August 12, 2015
Question

Merged Cells confuse the counter

  • August 12, 2015
  • 1 reply
  • 188 views

Hello community,

thanks in advance for any help, idea, comment!

I have a weird issue: I browse via a JScript through a table in InDesign to update prices given by a .csv.

To do so,

- I search for a Part-Nr given by the .csv and draw the indexes (parentRow, parentColumn) from the matching cell

- then I jump one cell to the right and place the new price (also given by the csv)

That works fine, AS LONG AS there are no merged cells in the row involved. If there are merged cells, then the search-response is correct, but when I try to place the right price, it jumps one cell too far (because earlier in the row, two cells are merged to one cell). The funny thing is, that when I ask for parentColumn of the cell, where the price should land, the answer is right. But when I then try to place new content in exact this cell using the coordinates just given, it jumps one cell further as wanted???

Here the code-piece that is inflicted:

app.findTextPreferences.findWhat = "Part-Nr given from the csv";

var myHit = myDoc.findText();

if(myHit.length > 0){

    myCell = myHit[0].parent;

    myCell.parentRow.cells[myCell.parentColumn.index+1].contents = "Price given from the csv";

    }

Anyone an idea what causes that behaviour and what I can do to avoid it?

Thanks a lot!

Kosta

This topic has been closed for replies.

1 reply

G
G. Singelmann
Inspiring
August 12, 2015

You get the partnr cell by taking the parent of the found text. That, logically, is the correct cell.

Then you take the index of the parent column, let’s say "4" and try to put the price into the 5th cell of the row. Not into the cell whose parent column has the index "5", but the fifth cell.

If there are merged cells to the left, the fifth cell is the one whose parent column has the index "6".

I prefer using the name of the cells to avoid having to dabble with merged cells.

i.e.:

myCell = myHit[0].parent;

var myTable = myCell;

while (myTable.constructor.name != "Table") myTable = myTable.parent;

var myName = myCell.name.split(":");

myName[0] = myName[0] + 1;

myName = myName.join(":");

myTable.cells.itemByName( myName ).contents = "Price given from the csv";

(Haven’t tested this, but the principle is valid)

Terms & ConditionsAccessibility statement
Using the community Terms of use Privacy Cookie preferences Do not sell or share my personal information ad choicesAdChoices