UXP scripting: How do you REALLY get the page on which a selection resides?

Forum|Forum|12 days ago
February 10, 2026
3 답변들
119 조회

All the examples you find tell you to traverse up through the selection’s parents until you hit the Page object. But in my experience, you never do. The traversal goes:

InsertionPoint → TextFrame → Spread → Document → Application

Now what?

For the curious, here’s the code:

function getPage(obj)
{
	if (obj == null)
		return null;

	if (obj.constructor.name == "Page")
	{
		return obj;
	}
	else if(obj.constructor.name == "Application")
	{
		// If we reach the application, something is wrong. Prevent endless recursion.
		return null;
	}

	// Handle cases where the item might be in a text frame
	if (obj.parentTextFrames && obj.parentTextFrames.length > 0)
	{
		return getPage(obj.parentTextFrames[0]);
	}

	// Recursively go up the object model
	return getPage(obj.parent);
}

rob day

Community Expert

Hi @Thomas_Calvin , I assume you can write a while statement with UXB? That’s how I would do it with ExtendScript. This seems to work for text in nested tables, text on a path, anchored text:

var sp = getTextPage(app.selection[0])
alert("Selected Text Starts on Page " + sp)


/**
* Gets the starting page of the selected text 
* @ param s the selected text 
* @ return text se;lection’s page  
*/
function getTextPage(s){
    var b = false; 
    var a = []
    var pn
    if (s != undefined && s.hasOwnProperty("pointSize")) {
        while (!b) {
            if (s.constructor.name == "Spread" || s.constructor.name == "Story" ) {
                b = true
            } else {
                s = s.parent
                a.push(s)
            }
        } 
        if (a.length == 1) {
            if (app.selection[0].parentTextFrames[0].constructor.name == "TextPath") {
                pn = app.selection[0].parentTextFrames[0].parent.parentPage.name
            } else {
                pn = app.selection[0].parentTextFrames[0].parentPage.name
            }   
        } else {
            pn = a[a.length-2].parentPage.name
        }
        return pn
    }else{
        return "Please select some text"
    }   
}

T

Thomas_Calvin작성자

Inspiring

Thanks! I did get it working satisfactorily, but then discovered that app.activeWindow.activePage seems to work reliably, and solves the problem for my use case.

rob day

Community Expert

If this is for in-house use it might not matter, but the active page and the selection’s page can be different:

var ap = app.activeWindow.activePage.name
var sp = getTextPage(app.selection[0])
alert("\nSelected Text Starts on Page " + sp + "\n Active Page is " + ap)

Peter Kahrel

Community Expert

[Edit: I hadn’t spotted the replies after Dirk’s doomesday scenario. Have to get used to collapsed threads!]

> All the examples you find tell you to traverse up through the selection’s parents until you hit the Page object.

The entity that you asked this question lives in the past. The function you showed dates back to Dave Saunders, who started using it many years ago.

As @leo.r and @Dirk Becker mention, you should use the parentPage property. You would first try to get a reference the the selection’s parentTextFrame, then return the text frame’s parent page. Something like

myInsertionPoint.parentTextFrames[0].parentPage;

You should of course take into account all scenarios that Dirk warned about (overset text, not on a page, etc). So you would tread carefully, look before you leap, etc etc, vaguely as in

// ip is an insertion point

if (ip.parentTextFrames.length > 0 // Not overset text
    && ip.parentTextFrames[0].parentPage != null) { // On a page
  // return the page
} else {
  // report and/or handle the situation
}