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Participant
April 3, 2018
Question

White Spot on Non-White Paper

  • April 3, 2018
  • 1 reply
  • 499 views

Been looking for an answer to this without any luck.

I'm trying to simulate a White Ink Spot on a non-white Paper (for instance a white ink on cardboard). 

It would seem that when the Paper Color is changed, it applies an overall tone without allowing any element to inherit a lighter tone than the paper.  Is there a setting I'm missing?

Paper Color set to K:50% with text set to a Lab: 100%L Spot

First image with OverPrintPreview: off

Second image with OverPrintPreview: on

I need this to look correct with OverPrintPreview on as there are other printing effects that need to preview correctly.

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1 reply

Eric Dumas
Community Expert
Community Expert
April 3, 2018

As far as I remember, changing the colour of paper on simulates the coloured paper, it has no intention of printing that colour, it assumes your paper is already 50%K. So overprint cannot really show the correct result.

Are you planning to print using white ink on grey paper?

Participant
April 3, 2018

I plan on printing a White Ink on cardboard. I understand that it will not print the paper color, but for simulation purposes I would like the paper color to be non-white.  But I would like the White Ink portions to appear 'whiter' than the substrate.

Also, another application I have planned, is printing 4-color on a transparent film.  The product will need to overprint on a Spot White (so it maintains it's highlights and full color range) while the shadow of said product will not (thus being printed on the clear film). 

I hope I have explained that sufficiently.

-Robert

Community Expert
April 4, 2018

Hi Robert,

I think, you cannot simulate this with InDesign.

Other than using a filled rectangle in the background as your paper simulation.

Tried some things with the ink manager with a spot color: Changes in ink density, opaque vs non-opaque and a simulation of the paper with a color profile. Also tried to define the spot color with CMYK 0|0|0|0…

Would be glad if someone could proof the contrary…

Regards,
Uwe