Cancelling subscription (paid monthly)

[Neem34082164gq95]

I want to cancel my subscription for which I pay monthly but also avoid any cancellation fee that they are charging when I try to cancel. How do I do that and avoid cancellation fee?

[kglad · Accepted solution]

you may not be able to do that unless you're within the cancellation window (14 days from trial start date), or you change to another plan.

make sure you're aware of the cancellation terms by selecting your plan type (at the top of the page here), https://helpx.adobe.com/manage-account/using/creative-cloud-subscription-terms.html

for info on how to cancel your subscription, this page describes the few steps involved, https://helpx.adobe.com/manage-account/using/cancel-subscription.html

if you want to cancel but are unable to follow the steps described in the "how to cancel page", contact adobe support.

there are 2 ways to contact adobe; chat and twitter (now x):

chat:
use a browser that allows popups and cookies, and click here, https://helpx.adobe.com/contact.html?rghtup=autoOpen
in the chat field (lower right), type AGENT
be patient, it can take quite a while to reach a human.

twitter/x:
tweet @AdobeCare

p.s. if you're contacted by anyone (via email or private message), it's much more likely to be a scammer than an adobe representative.

[deborah_0819]

Credit card stolen no way to pay you, I will ;let you know when things clear.  

[kglad]

@deborah_0819 

after contacting your credit card provider (hopefully already done), contact adobe support: there are 2 ways to contact adobe support; chat and twitter (now x):

chat:
if you have or want to purchase a subscription, use a browser that allows popups and cookies
and click here, https://helpx.adobe.com/contact.html?rghtup=autoOpen
in the chat field (lower right), type AGENT
be patient, it can take quite a while to reach a human.

twitter/x:
tweet @AdobeCare

p.s. if you're contacted by anyone (via email or private message), it's much more likely to be a scammer than an adobe representative.