match pattern and get the position using javascript in illustrator.

[rarur97798982]

Hi,

I need to get the position of a pattern in a text and store it in an array.

for example, consider the string

a^{^{x^{1}}}

I need to get all the positions of '{' and '}' to be stored in an array named supB;

Thanks in advance for the help.

[Mylenium]

I'm not clear what you are having issues with. A simple loop counting through the characters and using  .push() to add them to an array will do.

Mylenium

[rarur97798982]

if(documents.length >0){  //if document is open 
    if(app.activeDocument.selection[0]){  //if a line is selected 
        var supBPosition=[];
        var subBPosition=[];
        var doc = app.activeDocument;  //getting the active document
        var line = doc.pathItems[0];  //getting path items from the active document 
        var firstPoint = line.pathPoints[0].anchor; // [x, y]
        var lastPoint = line.pathPoints[line.pathPoints.length - 1].anchor; // [x, y]       
        var eqValues = (prompt("Enter something ", "", "")); //getting the values to write
        var eqValuesCopy=eqValues;
        var startCharacterSize=0;
        var ys=[];
        for(var i=0;i<eqValuesCopy.length;i++){
            if(eqValuesCopy.indexOf("{")>=0){
                ys.push(eqValuesCopy.indexOf("{"));
                startCharacterSize=eqValuesCopy.indexOf("{");
                eqValuesCopy=eqValuesCopy.slice(startCharacterSize);
            }
        }
    }
}

I don't get whats wrong in my loop

[Disposition_Dev]

I'm not 100% sure what you need this to do, but based on my assumptions from this post as well as your other post about equations, i put this together. This will give you two arrays, one for open brackets and one for close brackets. This should allow you to target specific textRanges by character index and apply the necessary characterAttributes for subscript, superscript etc.

Of course some error handling and validation of the user's input would be quite necessary, but this should point you in the right direction, i hope.

function test()
{
    var supBPosition = [];
    var subBPosition = [];
    var doc = app.activeDocument; //getting the active document  
    var line = doc.pathItems[0]; //getting path items from the active document   
    var firstPoint = line.pathPoints[0].anchor; // [x, y]  
    var lastPoint = line.pathPoints[line.pathPoints.length - 1].anchor; // [x, y]         
    var eqValues = (prompt("Enter something ", "", "")); //getting the values to write  
    var openBrackets = [];
    var closeBrackets = [];
    for(var x=0,len=eqValues.length;x<len;x++)
    {
        if(eqValues === "{")
        {
            openBrackets.push(x);
        }
        else if(eqValues === "}")
        {
            closeBrackets.push(x);
        }
    }
    alert("Results:\nThere are open brackets at the following indexes: " + openBrackets + 
        "\nThere are close brackets at the following indexes: " + closeBrackets);
}
if(app.documents.length && app.activeDocument.selection.length)
{
    test();
}

[pixxxelschubser · Accepted solution]

Hmmh?

I hope I understand you right. How about:

var aCon = "a^{^{x^{1}}}";
var reg = /[{}]/g;
var res;
while (res = reg.exec(aCon)) {
    $.writeln(res[0] + " | " + res.index);
}

If so, have fun

[CarlosCanto]

the king of regExp does it again!!!

[rarur97798982]

Thanks ... that worked...