Find the maxi height of the rectangle on a page

[Guest]

Hi Forum,

Your help is much appreciated.

I would like to check the rectangle which is the tallest of all, on each and every page, and write it in a txt file.

Here is my try. I can write only the first page rectangle height.

writeData();

function writeData (aData ) 

{ 

            tt= [];

    myFile = new File("/Users/astudio/Desktop/Info/rectangle.txt");

    if( myFile!='' ) 

    {  

        //Open the file for writing.  

        myResult = myFile.open( 'w', undefined, undefined );  

    } 

rct  = app.activeDocument.pages.everyItem().rectangles.everyItem().getElements();

for(i=0; i<rct.length; i++) {

rcc =     rct.rectangles.everyItem().getElements()

tt.push((rct.geometricBounds[2]-rct.geometricBounds[0]));

var myarray = tt;

var tf = myarray.sort(SortLowToHigh).pop();

myFile.writeln(rct.geometricBounds[2]-rct.geometricBounds[0]);     

function SortLowToHigh(a, b)  {

if (a > b) return 1;

else if (a < b) return -1;

else return 0;

}

myFile.close();  

continue;                /// I can't able to write the maximum height of the rectangle for next next pages..... one below the other in Text file.

    }  

}

Please help me out to get this done.

thanks very much.

[Guest]

Sorry forum a small correction

var tf = myarray.sort(SortLowToHigh).pop();

myFile.writeln(rct.geometricBounds[2]-rct.geometricBounds[0]);    

However it writes all the rectangles heights and not the tallest of all.

thanks.

[Guest]

Again, forum for more Information...

I tested, it writes like this.

30.5671641790929

18.1492537313365

16

9.50000000000001

44.6567164181409

26.5149253732712

but,

page 1 rectangles height.....

30.5671641790929              // I need to write only the tallest rectangle of page 1

18.1492537313365

page 2 rectangles height

16                                         // I need to write only the tallest rectangle of page 2

9.50000000000001

page 3 rectangles height

44.6567164181409         // I need to write only the tallest rectangle of page 3

26.5149253732712

thanks forum.

[Kai Rübsamen · Accepted solution]

He, why don’t you use the code-editor?

To find the tallest rectangle on every page, I would do something like:

var curDoc = app.activeDocument;
var allPages = curDoc.pages;
var list = [];

for ( var p = 0; p < allPages.length; p++ ) {
    var curPage = allPages
;
    var curPageRectangles = curPage.rectangles;
    var theTallestHeight = curPageRectangles[0];
    for ( var r = 1; r < curPageRectangles.length; r++ ) {
        var curRect = curPage.rectangles;
        if ( curRect.visibleBounds[2] - curRect.visibleBounds[0] > theTallestHeight.visibleBounds[2] - theTallestHeight.visibleBounds[0] ) {
            theTallestHeight = curRect;
        }
    }
    list.push( "Page " + theTallestHeight.parentPage.name + ": " + String( theTallestHeight.visibleBounds[2] - theTallestHeight.visibleBounds[0] ) );
}
alert ( list.join( "\r" ) );

[Guest]

Hi Kai Rübsamen

Thanks for your valuable support.

Kai, I have a doubt on this. When i tried to retain only the tallest rectangle on page, deleting other. The script doesn't consider the recently added tallest rectangle.

The recently added rectangle hasn't been considered as Item(0) (curPageRectangles[0];).

Any help please.

THanks for your support on time. timely indeed.

[Kai Rübsamen]

Hm, sorry but I did not understand the problem … maybe some advanced scripters see something that I’m not aware of.

Assume you have 4 rectangles. The script take curDocRectangles[0] and assumes, that this one is the tallest one.

If you create a new rectangle, this new one get the index 0. So if you start the script again, this rectangle will be check at first.

So, if you have a problem with this, try to built a example, where the script goes wrong and try to describe in good english your steps.

– Kai

[Guest]

Kai, thank you so much for your extensive support.

I'm really sorry for the communication issue.

Please bear with me for the inconvenience.

I will update you, what Im trying to get from you.

thanks for the support kai.

[Guest]

Hi kai,

I'm just trying to delete all the smallest height rectangles leaving the tallest one intact.

The script edited (the one you helped me).

var curDoc = app.activeDocument; 

var allPages = curDoc.pages; 

var list = []; 

for ( var p = 0; p < allPages.length; p++ ) { 

    var curPage = allPages

; 

    var curPageRectangles = curPage.rectangles; 

var theTallestHeight = curPageRectangles[0]; 

    for ( var r = 1; r < curPageRectangles.length; r++ ) { 

var curRect = curPage.rectangles;

if(curRect.visibleBounds[2] - curRect.visibleBounds[0]!=String( theTallestHeight.visibleBounds[2] - theTallestHeight.visibleBounds[0] )) {

  curRect.remove();

}

}

}   

As you said, Let's assume, I have 4 rectangles on each pages, with different heights.

After running the edited script (above), only 1 smallest height rectangle is deleted on all the pages.

My intention is to delete all the 3 smallest rectangle, except the 1, the tallest rectangle on each page.

Thanks for the support Kai,

[Guest]

Hi Kai,

Thanks for your help & support.

Temporarily I have found something like this. Just tweaked your script.
Please correct me if I went wrong here.

var curDoc = app.activeDocument; 

var allPages = curDoc.pages; 

var list = []; 

for ( var p = 0; p < allPages.length; p++ ) { 

    var curPage = allPages

; 

    var curPageRectangles = curPage.rectangles; 

var theTallestHeight = curPageRectangles[0]; 

    for ( var r = 1;  r<curPageRectangles.length-1;  r++) { 

var curRect = curPage.rectangles;

if(curRect.visibleBounds[2] - curRect.visibleBounds[0]<String( theTallestHeight.visibleBounds[2] - theTallestHeight.visibleBounds[0] )) {

        try {

do(curPage.rectangles.remove());

while(curPageRectangles[0]!=0 )

} catch (e) {}

}

}

}    

Kai, kindly correct the above script, to do much better & prettier.

Thanks for your support Kai.