2 Correct answers
Are you trying to get the actual (unscaled) pixel dimensions? An image has the effective ppi resolution property, so if the document units are set to inches, you can get the pixel dimensions. This gets the actual pixel (or inch) dimensions of a selected image:
var doc = app.activeDocument;
doc.viewPreferences.properties = {horizontalMeasurementUnits:MeasurementUnits.INCHES, verticalMeasurementUnits:MeasurementUnits.INCHES}
//a selected image
var sel = doc.selection[0];
//the actual pixel d
You can get the scale by dividing the Effective by Actual Res. Direct select an image and try this:
var s = app.activeDocument.selection[0]
//width and height as na array
var d = getWidthHeight(s);
if (s.constructor.name == "Image") {
var ep = s.effectivePpi
var ap = s.actualPpi
var w = (ep[0]/ap[0]) * d[0];
var h = (ep[1]/ap[1]) * d[1]
alert(w.toFixed (3) + " x " + h.toFixed (3))
} else {alert("Select an Image")}
/**
* Get a page item’s width and height
* @ param the page
43
Replies
Another way to handle the styling might be to make or use an Object Style, which can include a Paragraph Style property. In this case I’ve added a function that will return an Object Style named "Label" if it exists, and if it doesn’t it will make one, which can then be applied to the new text frame’s properties.
main()
function main(){
var ot = app.transformPreferences.transformationsAreTotals
app.scriptPreferences.measurementUnit = MeasurementUnits.MILLIMETERS;
app.transformPreferences.transformationsAreTotals = true;
//an object style for the label text frame
var os = makeObjStyle(app.activeDocument, "Label")
var s = app.activeDocument.selection[0];
var lnk;
if (s!=undefined && s.constructor.name == "Image" || s.constructor.name == "PDF") {
lnk = s.itemLink
} else {
try {
lnk = s.allPageItems[0].itemLink;
}catch(e) {
alert("Please Select a Linked Item")
return
}
}
var p = lnk.parent.parent;
var d = getActualDim(p)
var b = p.geometricBounds;
var pp = p.parentPage;
var dt = lnk.name + "\t" + d[0].toFixed (3) + " x " + d[1].toFixed (3)+" mm"
//add the label to the bottom of the image
pp.textFrames.add({fillColor:"Paper", geometricBounds: [b[2],b[1],b[2]+5,b[3]], contents:dt, appliedObjectStyle:os});
app.transformPreferences.transformationsAreTotals = ot;
app.scriptPreferences.measurementUnit = AutoEnum.AUTO_VALUE;
}
/**
* Gets a link’s actual dimensions
* @ param the placed object
* @ return the object’s actual width and height as an array
*/
function getActualDim(lnk){
var d = getWidthHeight(lnk);
var sw = lnk.horizontalScale;
var sh = lnk.verticalScale;
var w = (100/sw) * d[0];
var h = (100/sh) * d[1];
return [w,h]
}
/**
* Get a page item’s width and height
* @ param the page item
* @ return an array [width, height]
*/
function getWidthHeight(pi){
var gb = pi.geometricBounds
return [gb[3]-gb[1], gb[2]-gb[0]]
}
/**
* Makes a new named ObjectStyle or returns an existing style
* @ param the document to add the style to
* @ param style name
* @ return the new object style
*/
function makeObjStyle(d, n){
if (d.objectStyles.itemByName(n).isValid) {
return d.objectStyles.itemByName(n);
} else {
return d.objectStyles.add({name:n});
}
}
Thats brilliant Rob with the Object style, however im back to the issue of it displaying the box size and not the link size. The code on Williams script works but i cannot style the box like your one.
On this example Williams output is on the top and correct and yours in on the bottom (ive not styled it here but know how to)
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