Help with GREP search

[GeofferyH]

I'm trying to change 01, 02, 03, up to 09 and change to the digit without the 0 (zero).

Thanks in advance,

Geoff

[Obi-wan Kenobi]

I don't understand. Specifically...? Thank you to give us samples?

[GeofferyH]

Sorry, yes, I have class information that has dates, times and hours.  I want to change May 04 to May 4, May 07 to May 7 and so on. Just need to delete the zero in the dates while keeping the zero's in times, e.g. 10:30 p.m.

[Obi-wan Kenobi]

So:

Search: (January|February|March|April|May|June|July|August|September|October|November|December)(\s0)

Replace: $1~S

[GeofferyH]

Thank you Obi-wan.

[GeofferyH]

I understand the search, can you explain what $1~S is saying?

[Obi-wan Kenobi]

Hi,

When we make a regex (grep search/replace), we often use code between (). Grep calls this "sous-expression marquante" (in french). If we write two "sous-expressions marquantes" as: (January)(\s0), in the replace input box, $1 reproduce "January", the first instance between (), (any space + zero) can be reproduced by $2. So if I finally choose "$1~S, that means: I replace (January) by: January (the () are forgotten) and ~S is the grep syntax of an nonbreaking space. (\s0), so (any space + zero), is not taken into account and finally non treated.

So, if I search: "January 0", when I find it, I replace it by: "January " (here, the space is a nonbreaking space (better for what you want!).

I suggest you to read all what you can find on Grep. With JavaScript and imagination, you have the 3 more important tools to work fine! 

[GeofferyH]

ok, yes, thanks again, that's what I thought, just wanted to be sure I it understood correctly.

[Luis_Fernando_Brito]

@GeofferyH use the following expression:

Find: (0{1})([1,2,3,9])

change: $2