Using grep to find and style "any white space followed by =, < or >"

[dianar38503025]

Hi all,

I am trying to use grep in a paragraph style to automatically italicise p numbers. (mentions of p = 0.001, p > 0.0001)

Basically, I need to style every time there is a p followed by any white space followed by either =,< or >.

So far I can get it to work without the white spaces using: p(?=[\=]|[\r>]|[\r<]) which will style mentions of p= 0.001, p> 0.0001.

Where I am struggling is how to add in the any white space.

I have tried adding in in \s but wherever I put this it adds the italic style to everywhere there is p then white space, even if this is at the end of a word.

Any suggestions?

[Chad Chelius]

Try (?<=[\p\s])[\=|\<|\>]

I just put brackets around the p and space in the positive look behind.

[dianar38503025]

Thanks for the suggestion,

I have just tried using (?<=[\p\s])[\=|\<|\>] and it does not seem to pick anything up in my styles

[FRIdNGE · Accepted solution]

Find:  p\h?(?=[=<>])

Replace by:  p~s + italic

Best,

Michel, from FRIdNGE

[dianar38503025]

Yes that works! Thank you.